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iragen [17]
3 years ago
15

A 39.7 n object is in free fall. what is the magnitude of the net force which acts on the object? answer in units of n.

Physics
1 answer:
Vika [28.1K]3 years ago
6 0
If there is no air resistance, the value would still be the same. So therefore, the answer is 39.7 N.
Supposing that there is an air resistance of 19.8 N.With a 19.8 N air resistance: ∑F = 39.7 N - 19.8 N = 19.9 N would be the net force. The important point here is that the force of gravity equivalent the weight of the object.
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Boats use echo sounders. Pulses of sound waves are reflected by the sea bed and
Sati [7]

Answer: depth = 3.75 m

Explanation:

Taken the speed of the sound in sea to be V = 1500 m/s

The time between an echo sounder sending and receiving a pulse is 0.005 s. That is,

Total time T = 0.005

Formula for echo is:

V = 2X/T

Where X = distance covered

Substitute V and T into the formula

1500 = 2X/0.005

Cross multiply

7.5 = 2X

Make X the subject of formula

X = 7.5/2

X = 3.75 m

Therefore, the depth of the sea is 3.75 m

4 0
3 years ago
Guitar string has an overall length of 1.22 m and a total mass of 3.5 g before being strung on a guitar. Once it is used on the
ikadub [295]

Answer:

Fundamental frequency= 174.5 hz

Explanation:

We know

fundamental frequency=\frac{velocity}{2 *length}

velocity =\sqrt{\frac{tension}{mass per unit length} }

mass per unit length=\frac{3.5}{1000*1.22}=0.00427\frac{kg}{m}

Now calculating velocity v=\sqrt{\frac{255}{0.00427} }

                                           =244.3\frac{m}{sec}

Distance between two nodes is 0.7 m.

Plugging these values into to calculate frequency

f = \frac{244.3}{2 *0.7} =174.5 hz

6 0
3 years ago
Who was the fist man on moon
laila [671]

Answer:

Neil Armstrong

Explanation:

3 0
2 years ago
Read 2 more answers
The derived unit for density are g/cm3.<br><br> True<br> False
anzhelika [568]
True, the measurement shown is a derived unit.
6 0
2 years ago
Using hooke's law find the elastic constant of a spring that stretches 2 cm when 4newton force is applied to it
Kay [80]

<u>Answer:</u>

2N/cm

<u>Step-by-step explanation:</u>

According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:

F=kx

where, F is the force which is stretching or compressing the spring,

k is the spring constant; and

x is the distance the spring is stretched.

Substituting the given values to find the elastic constant  k to get:

F=kx

4=k(2)

k=\frac{4}{2}

k=2

Therefore, the elastic constant is 2 Newton/cm.

3 0
2 years ago
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