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kap26 [50]
3 years ago
14

PLZ ANSWER ASAP IF YOU KNOW THIS...At the county fair, Carrie and Sam climbed up on the carousel horses. Around and around they

went; the horses also bobbed up and down. When they got off of the carousel, Carrie told Sam they had been accelerating during their ride. Sam disagreed; they had been moving at a constant speed. Whose response is fully correct, and why?
A) Carrie is, because the carousel changed speed when it started and stopped. B) Sam is, because the horses never moved from their position on the carousel. C) Carrie is, because velocity includes speed plus direction, and both changed. D) Sam is, they did not accelerate since their speed remained constant for the ride.
Physics
1 answer:
Maslowich3 years ago
8 0
The answer is (a) because movement is acceleration 
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A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
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2 years ago
A plane flies 446 km east from city A to city B in 43.0 min and then 939 km south from city B to city C in 1.10 h. For the total
NeTakaya

Answer:

(a) Magnitude is 1039 km

(b) Direction of the displacement is 64.59^{\circ} South of East

(c) Average velocity magnitude is 570.88 km

(d) The direction of average velocity is 64.59^{\circ} South of East

(e) Average speed is 759.34 km/h

Solution:

Distance moved from A to B in East direction, \vec{AB} = 446 km

Distance moved from B to C in South direction, \vec{BC} = - 939 km

Time taken to move from A to B, t = 43.0 min = 0.72 h

Time taken to move from B to C, t' = 1.10 h

Now,

(a) The magnitude of displacement of the plane is provided by AC as shown in fig 1 and can be given as:

AC = \sqrt{(AB)^{2} + (BC)^{2}}

AC = \sqrt{(446)^{2} + (- 939)^{2}} = 1039 km

(b) Direction of the displacement is given by:

tan\theta = \frac{\vec{BC}}{\vec{AB}}

\theta = tan^{- 1}(\frac{- 939}{\vec{446}}) = - 64.59^{\circ}

64.59^{\circ} South of East

(c) Magnitude of the average speed is given by:

v_{avg} = \frac{AC}{t + t'}

v_{avg} = \frac{1039}{1.82} = 570.88 km/h

(d) The direction of the average velocity is the same as that of the displacement, i.e., 64.59^{\circ} South of East.

(e) The average speed of the [plane is given by:

v'_{avg} = \frac{Total\ Distance\ Traveled}{Total\ Time}

v'_{avg} = \frac{446 + 939}{1.10 + 0.72} = 759.34 km/h

6 0
3 years ago
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