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zhenek [66]
3 years ago
12

Please help me with 1,2,3,4,5,6

Physics
1 answer:
Trava [24]3 years ago
3 0
I know that 4. Is wave 2 and 5. Is wave 3.
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Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. Assume free fall.
xxMikexx [17]

Answer:

36s

Explanation:

Let the objects be A and B.

Let the initial velocity of A be U and the initial velocity of B be 3U

The height sustain by A will be;

The final velocity would be zero

V2 = U2-2gH

Hence

0^2= U2 -2gH

H = U^2/2g

Similarly for object B, the height sustain is;

V2 = (3U)^2-2gH

Hence

0^2= 3U^2 -2gH

U2-2gH

Hence

0^2= U2 -2gH

H = 3U^2/2g

By comparism. The object with higher velocity sustains more height and so should fall longer than object A.

Now object A would take;

From V=U+gt as the object falls freely, the initial velocity is zero hence and the final velocity of the object is;

V=10×12=120m/s let g be 10m/S2

Similarly for object B,

The final velocity for B when it's falling it should be 3×that of A

Meaning

3V= gt

t =3V/g = 3× 120/10 = 36s

3 0
3 years ago
Could someone help me with this please?
ycow [4]

Answer:

you could measure several properties of

the unknown liquid and compare them with the properties of known

substances. You might observe and measure such properties as color,

odor, texture, density, boiling point, and freezing point.

6 0
3 years ago
Read 2 more answers
In the following free body diagram, what is the net force on the object?
frozen [14]

Answer:

B

Explanation:

Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.

ΣF = 7 + 18 + (-20) = 5N to the right

3 0
2 years ago
What total distance will a sound wave travel in air in 3.00 seconds at stp?
dimaraw [331]
At stp conditions (T=0^{\circ}C), the speed of sound is
v=331.2 m/s
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
S=vt
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
S=vt=(331.2 m/s)(3.00 s)=993.6 m
4 0
3 years ago
A crate of mass 50kg is pushed along a floor with a force of 20N for a distance of
PSYCHO15rus [73]

Answer:

F=50kg

D=5m

W=FD

therefore work done is 250Nm

8 0
2 years ago
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