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inessss [21]
3 years ago
13

Jay bought a toy car. To make the car move, he must turn a key attached to a spring. Turning the key winds the spring tight. The

toy car moves when the key is released and the spring unwinds. What’s the main transformation of energy in this example?
Physics
2 answers:
lapo4ka [179]3 years ago
5 0
The chemical energy in Jay's body, to kinetic energy in the car
Brilliant_brown [7]3 years ago
4 0

Answer:

Elastic potential energy into kinetic energy

Explanation:

Initially, all the energy is stored in the spring, which is compressed. This energy is called elastic potential energy, and it is equal to

U=\frac{1}{2}kx^2

where k is the spring constant and x is the compression of the spring. When the key is turned, the spring is released, and all this energy is converted into kinetic energy, which is the energy due to the motion of the car. The equation that gives this energy is

K=\frac{1}{2}mv^2

where m is the mass of the car and v is the speed of the car.

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What would make oppositely charged objects attract each other more?
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A. increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object

Explanation:

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I. The spring does work on the box from the moment the box first hits the spring to the moment the spring first reaches its maxi
nalin [4]

Answer:

Negative

Explanation:

If the box is heading right in the positive direction, the work will be negative. The spring has an opposite force to that of the box.

Hope this helped. :)

6 0
3 years ago
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Novay_Z [31]

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

4 0
3 years ago
When reaching a boundary between two media (1 and 2), an incident ray is partially reflected and partially refracted. The ray is
lukranit [14]

Answer:

The angle of incidence when the reflected ray is perpendicular to the incident ray = 45°

Explanation:

According to Snell's Law,

n₁ sin θ₁ = n₂ sin θ₂

When the angle between the incident ray and reflected ray is 90°, the angle of incidence is θ₁ and the angle of reflection, θ₂ = 90° - θ₁ and the index of refraction in the Snell's Law for both media would be the same, n₁ = n₂ = n

n sin θ₁ = n sin (90° - θ₁)

Note that from trigonometric relations,

Sin (90° - θ₁) = cos θ₁

n sin θ₁ = n cos θ₁

(sin θ₁)/(cos θ₁) = 1

tan θ₁ = 1

θ₁ = arctan 1 = 45°

Hope this Helps!!!

7 0
4 years ago
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