All categories

2 years ago

Preferential stress will cause crystals to rotate into a preferred orientation unless the crystals are ________

Engineering

1 answer:

velikii [3]2 years ago

6 0

Answer:

Preferential stress will cause crystals to rotate into a preferred orientation unless the crystals are Equant

You might be interested in

In casting experiments performed using a certain alloy and type of sand mold, it took 155 sec for a cube-shaped casting to solid

Tems11 [23]

Answer:

A) Cm = 2.232 s/mm²

B) Time taken to solidify = 74.3 seconds

Explanation:

(A) Since a side is 50mm and all sides of a cube are equal, thus, Volume of the cube is;V = 50 x 50 x 50 = 125,000 mm³

There are 6 faces of the cube, thus Surface Area A = 6 x (50 x 50) = 15,000 mm²

So, Volume/Area = (V/A) = 125,000/15,000 = 8.333 mm

Cm is given by the formula; Cm =[Tts] /(V/A)² where Tts is time taken to solidify and it's 155 seconds in the question. Thus;

Cm = 155/(8.333)²= 2.232 s/mm²

(B) For;Cylindrical casting with D = 30 mm and L = 50 mm.;

Volume of cylinder is;

V = (πD²L) /4

So,V = (π x 30² x 50)/4 = 35,343mm³

Surface area of cylinder is;

A = (2πD²)/4 + (πDL)

Thus, A = ((π x 30²)/2) + (π x 30 x 50) = 6126 mm²

Volume/Area is;

V/A = 35,343/6126 = 5.77 mm

Same alloy and mold type was hsed as in a above, thus, Cm is still 2.232 s/mm²

Since Cm =[Tts] /(V/A)²

Making Tts the subject, we have;

Tts =Cm x (V/A)²

Tts = 2.232 x (5.77)² = 74.3 seconds

3 0

3 years ago

A vertical cylinder (Fig. P3.227) has a 61.18-kg piston locked with a pin, trapping 10 L of R-410a at 10◦C with 90% quality insi

Whitepunk [10]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

4 0

3 years ago

Trent is designing the grounds for a massive outdoor skate park. He has no experience with skateboarding at all, and although he

alexandr1967 [171]

Answer:

I’m sorry I don’t understand this is there more steps?‍♀️

Explanation:

8 0

3 years ago

Read 2 more answers

A small object A is held against the vertical side of the rotating cylindrical container of radius r by centrifugal action. If t

xxMikexx [17]

Answer:

el radius es coeficiente por que determina la expresión

8 0

3 years ago

How much power would you need to cool down a closed, 1 Liter container of water from 100°C to 20°C in 5 minutes? (a) 1.1W (b)1.1

qaws [65]

Answer:

The power required to cool the water is 1.11Kw.

Hence the correct option is (b).

Explanation:

Power needed to cool down is equal to heat extract from the water.

Given:

Volume of water is 1 liter.

Initial temperature is 100C.

Final temperature is 20C.

Time is 5 minutes.

Take density of water as 100 kg/m3.

Specific heat of water is 4.186 kj/kgK.

Calculation:

Step1

Mass of the water is calculated as follows:

$\rho=\frac{m}{V}$

$1000=\frac{m}{(1l)(\frac{1m^{3}}{1000l})}$

m=1kg

Step2

Amount of heat extraction is calculated as follows:

$Q=mc\bigtriangleup T$

$Q=1(4.186kj/kgk)(\frac{1000 j/kgk}{1 kj/kgk})\times(100-20)$

Q=334880 j.

Step3

Power to cool the water is calculated as follows:

$P=\frac{Q}{t}$

$P=\frac{334880}{(5min)(\frac{60s}{1min})}$

P=1116.26W

$P=(1116.26W)(\frac{1Kw}{1000 W})$

P=1.11 Kw.

Thus, the power required to cool the water is 1.11Kw.

Hence the correct option is (b).

8 0

4 years ago