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3 years ago

Define the difference between elastic and plastic deformation in terms of the effect on the crystal lattice structure.

Engineering

1 answer:

grin007 [14]3 years ago

3 0

Answer:

Elastic Deformation:

Elastic deformation is due to the elasticity of the body i.e., the deformation disappears on removal of external forces and the lattice regain its original structure.
This type of deformation is temporary in nature.
This type of deformation depends mainly on the chemical bonding of the substance.
It occurs due to bending or stretching of chemical bond under applied stress where atoms do not slip pass over each other.
It is a reversible process.

Plastic Deformation:

Plastic deformation is due to the plasticity of the body i,e., the structure can be easily shaped or molded .
This type of deformation is permanent in nature.
This type of deformation occurs mainly due to breakage of chemical bonds(limited in number) between constituent atoms.
Atoms may slip pass each other causing dislocation of atoms , resulting in permanent deformation even after stress is removed.
It is an irreversible process.

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Thrust is managed to maintain IAS, and glide slope is being flown. What characteristics should be observed when a headwind shear

SVEN [57.7K]

The characteristics that can be observed when a headwind shears to be a constant tailwind are:

Pitch attitude: decreases.
Required thrust: increased then reduced.
Vertical Speed: increases.
Indicated airspeed (IAS): decreases, then increases to approach speed.

<h3>What is thrust?</h3>

Thrust can be defined a force that moves an aircraft or a flying machine through the air, especially in the direction of the motion.

<h3>The importance of thrust.</h3>

Generally, thrust is used in aeronautic engineering to achieve the following:

To overcome the weight of a rocket.

To overcome the drag of an aircraft.

To maintain indicated airspeed (IAS).

To maintain glide slope being flown at.

Some of the characteristics that can be observed when a headwind shears to be a constant tailwind are:

Pitch attitude: decreases.
Required thrust: increased then reduced.
Vertical Speed: increases.
Indicated airspeed (IAS): decreases, then increases to approach speed.

Read more on thrust here: brainly.com/question/20068220

4 0

3 years ago

g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%

Bond [772]

Answer:

<em>Heat rejected to cold body = 3.81 kJ</em>

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

<em>efficiency of the Carnot's engine = 1 - </em> $\frac{Tc}{Th}$ <em> </em>

eff. of the Carnot's engine = 1 - $\frac{400}{600}$

eff = 1 - 0.25 = 0.75

<em>efficiency of the heat engine = 70% of 0.75 = 0.525</em>

work done by heat engine = 2 kJ

<em>eff. of heat engine is gotten as = W/Q</em>

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = <em>3.81 kJ</em>

6 0

3 years ago

Gina is about to use a fire extinguisher on a small fire. What factor determines the

Effectus [21]

Answer:

Each portable fire extinguisher should only be used for its specific type of fire. Class A extinguishers could cause a Class B fire to spread or electrocution in a Class C fire. A Class B extinguisher could fail to completely extinguish a Class A fire, causing the flame to re-ignite later.

7 0

3 years ago

Determine (with justification) whether the following systems are (i) memoryless, (ii) causal, (iii) invertible, (iv) stable, and

lina2011 [118]

Answer:

y[n] = x[n] x[n-1] x[n+1]

(i) Memory-less - It is not memory-less because the given system is depend on past or future values.

(ii) Causal - It is non-casual because the present value of output depend on the future value of input.

(iii) Invertible - It is invertible and the inverse of the given system is $\frac{1}{x[n] . x[n-1] x[n+1]}$

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is not time invariant because the system is multiplying with a time varying function.

y[n] = cos(x[n])

(i) Memory-less - It is memory-less because the given system is not depend on past or future values.

(ii) Causal - It is casual because the present value of output does not depend on the future value of input.

(iii) Invertible - It is not invertible because two or more than two input values can generate same output values .

For example - for x[n] = 0 , y[n] = cos(0) = 1

for x[n] = 2 $\pi$ , y[n] = cos(2 $\pi$ ) = 1

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is time invariant because the system is not multiplying with a time varying function.

3 0

3 years ago

A roller-coaster car is traveling at a speed of 23 m/s when it passes through point B. At that point, it enters a concave down c

ycow [4]

Answer:

See it in the pic

Explanation:

See it in the pic

8 0

3 years ago