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nirvana33 [79]
3 years ago
5

Define the difference between elastic and plastic deformation in terms of the effect on the crystal lattice structure.

Engineering
1 answer:
grin007 [14]3 years ago
3 0

Answer:

Elastic Deformation:

  • Elastic deformation is due to the elasticity of the body i.e., the deformation disappears on removal of external forces and the lattice regain its original structure.
  • This type of deformation is temporary  in nature.
  • This type of deformation depends mainly on the chemical bonding of the substance.
  • It occurs due to bending or stretching of chemical bond under applied stress where atoms do not slip pass over each other.
  • It is a reversible process.

Plastic Deformation:

  • Plastic deformation is due to the plasticity of the body i,e., the structure can be easily shaped or molded .
  • This type of deformation is permanent  in nature.
  • This type of deformation occurs mainly due to breakage of chemical bonds(limited in number) between constituent atoms.
  • Atoms may slip pass each other causing dislocation of atoms , resulting in permanent deformation even after stress is removed.
  • It is an irreversible process.
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Answer:

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Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

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Answer:

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