A cylindrical specimen of a metal alloy 45.8 mm long and 9.72 mm in diameter is stressed in tension. A true stress of 378 MPa ca
uses the specimen to plastically elongate to a length of 54.2 mm. If it is known that the strain-hardening exponent for this alloy is 0.2, calculate the true stress (in MPa) necessary to plastically elongate a specimen of this same material from a length of 45.8 mm to a length of 55.8 mm
1 answer:
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Answer:
y ≈ 2.5
Explanation:
Given data:
bottom width is 3 m
side slope is 1:2
discharge is 10 m^3/s
slope is 0.004
manning roughness coefficient is 0.015
manning equation is written as
where R is hydraulic radius
S = bed slope
P is perimeter
solving for y
solving for y value by using iteration method ,we get
y ≈ 2.5