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Aleksandr-060686 [28]
3 years ago
14

Using any of the bilinear transform, matched pole-zero, or impulse invariance techniques in converting a continuous-time system

to a discrete-time system will always preserve the system stability.
a. True
b. False
Engineering
2 answers:
leonid [27]3 years ago
4 0

Answer:

A. True

The bilinear transform is employed in digital signal processing and discrete-time control theory which helps in transforming continuous-time system representations to discrete-time

Natasha2012 [34]3 years ago
3 0

Answer:

A - TRUE

Explanation:

The bilinear transform (also known as Tustin's method) is usually applied in digital signal processing and discrete-time control theory. It is used to transform continuous-time system representations into discrete-time and vice versa.

This transform usually preserves stability and also maps every point of the frequency response of the continuous-time filter.

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all of the following are steps in the problem solving process except a. try, b. reflect, c. debug, d. define
IceJOKER [234]

Answer:

a

Explanation:

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2 years ago
What is required when setting up a smart phone as a WIFI hotspot?
emmainna [20.7K]
How to create a personal hot spot on an iPhone?

Go to Settings | Cellular | Personal Hotspot.

Tap the slider next to Allow Others to Join. ...

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5 0
3 years ago
A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a
IrinaVladis [17]

Answer:

The original length of the specimen l_{o} = 104.7 mm

Explanation:

Original diameter d_{o} = 30 mm

Final diameter d_{1} = 30.04 mm

Change in diameter Δd = 0.04 mm

Final length l_{1} = 105.20 mm

Elastic modulus E = 65.5 G pa = 65.5 × 10^{3} M pa

Shear modulus G = 25.4 G pa = 25.4 × 10^{3} M pa

We know that the relation between the shear modulus & elastic modulus is given by

G = \frac{E}{2(1 + \mu)}

25.5 = \frac{65.5}{2 (1 + \mu)}

\mu = 0.28

This is the value of possion's ratio.

We know that the possion's ratio is given by

\mu = \frac{\frac{0.04}{30} }{\frac{change \ in \ length}{l_{o} } }

{\frac{change \ in \ length}{l_{o} } = \frac{\frac{0.04}{30} }{0.28}

{\frac{change \ in \ length}{l_{o} } = 0.00476

\frac{l_{1} - l_{o}  }{l_{o}  } = 0.00476

\frac{l_{1} }{l_{o} } = 1.00476

Final length l_{o} = 105.2 m

Original length

l_{o} = \frac{105.2}{1.00476}

l_{o} = 104.7 mm

This is the original length of the specimen.

5 0
3 years ago
Locate the centroid y¯ of the composite area. Express your answer to three significant figures and include the appropriate units
german

Answer:

Please see the attached Picture for the complete answer.

Explanation:

4 0
3 years ago
A 20-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when o
ch4aika [34]

Answer:

1.887 m

Explanation:

(15 *pi)/180

= 0.2618 rad

Polar moment

= Pi*d⁴/32

= (22/7*20⁴)/32

= 15707.96

Torque on shaft

= ((22/7)*20³*110)/16

= 172857.14

= 172.8nm

Shear modulus

G = 79.3

L = Gjθ/T

= 79.3x10⁹x(1.571*10^-8)x0.2618/172.8

= 1.887 m

The length of the bar is therefore 1.887 meters

5 0
3 years ago
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