Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Answer:
This could represent something like sliding a small rock across an icy lake.
Explanation:
A 20N force of gravity (weight), and 20N normal force exerted back onto the object imply it is on the ground and has no vertical motion. There is a net force of 0N
An 80N force to the left and a 5N force to the right create a net force of 75N to the left. This means that there is a force acting on the object that makes it accelerate to the left. 80N represents a push or pull force and 5N represents a relatively small frictional force due to the object being slid on a surface such as steel or in this case ice.
(a) The reactance of the inductor is 25.46 ohms.
(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)
<h3>Ractance of the inductor</h3>
The reactance of the inductor is calculated as follows;
XL = ωL
where;
- ω is angular frequency
- L is 190 mH
v(t) = (161 V) sin(134t)
v(t) = V sin(ωt)
The reactance of the inductor is calculated as follows;
XL = (134) x (190 x 10⁻³)
XL = 25.46 ohms
<h3>Peak current in the circuit</h3>
I₀ = V₀/XL
I₀ = (161) / (25.46)
I₀ = 6.32 A
<h3>Expression for the current through the inductor</h3>
I(t) = (6.32 A) sin(134t)
Learn more about inductance here: brainly.com/question/16765199
Answer:
mr or ms please type ur question fully please
Energy cannot be created nor be destroyed
