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viktelen [127]
3 years ago
8

The primary coil of a transformer has N1 = 275 turns, and its secondary coil has N2 = 2,200 turns. If the input voltage across t

he primary coil is Δv = (160 V)sin ωt, what rms voltage is developed across the secondary coil?
Physics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

Secondary voltage of transformer is 905.23 volt  

Explanation:

It is given number of turns in primary of transformer N_1=275

Number of turns in secondary N_2=2200

Input voltage equation of the transformer

\Delta v=160sin\omega t

Here v_{max}=160volt

v_{rms}=\frac{160}{\sqrt{2}}=113.15volt

For transformer we know that

\frac{V_1}{V_2}=\frac{N_1}{N_2}

\frac{113.15}{V_2}=\frac{275}{2200}

V_2=905.23Volt

Therefore secondary voltage of transformer is 905.23 volt

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