Question

The primary coil of a transformer has N1 = 275 turns, and its secondary coil has N2 = 2,200 turns. If the input voltage across the primary coil is Δv = (160 V)sin ωt, what rms voltage is developed across the secondary coil?

Answer 1

Answer:

Secondary voltage of transformer is 905.23 volt  

Explanation:

It is given number of turns in primary of transformer $N_1=275$

Number of turns in secondary $N_2=2200$

Input voltage equation of the transformer

$\Delta v=160sin\omega t$

Here $v_{max}=160volt$

$v_{rms}=\frac{160}{\sqrt{2}}=113.15volt$

For transformer we know that

$\frac{V_1}{V_2}=\frac{N_1}{N_2}$

$\frac{113.15}{V_2}=\frac{275}{2200}$

$V_2=905.23Volt$

Therefore secondary voltage of transformer is 905.23 volt