Supposing the person has insignificant height, we have that the angle of elevation is connected to the height of rocket and distance from spectator by:
tan(θ) = H/D (opposite is height, adjacent is distance)
Taking the derivative of both sides with respect to time:
d/dt (tan(θ(t))) = v/D (where v is the velocity of the firework)
Using chain rule on the left side:
sec2(θ)*(dθ/dt) = v/D
dθ/dt = cos2(θ)*v/D
When the firework is 30 feet above the ground, θ = tan-1(30ft/15ft) = 0.540 rad
dθ/dt = [ 1 / (1 + 1) ]*(11)/15
= (1/2)(1/15)*(11)
= 11/100
= 0.011 radians /s
It is correct to state that if you are looking at the sky from the continental United States, the north celestial pole would have an angular height (an altitude) equal to your latitude.
<h3>
What is the North Celestial Pole?</h3>
The point at where the earth's extended axis intersects the northern half of the celestial sphere, around 1° from Polaris.
These dots trace out circles in the sky due to precession. Today, the north celestial pole is only 1° from Polaris. Around 2100 ce, it will be closest to Polaris.
Learn more about the North Celestial Pole:
brainly.com/question/17372686
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I'm going without any details here.
The projectile would have the greatest velocity if thrown from a high distance, it would also help depending on what the gravity was which on earth would help increase the velocity since it's strong and pull more on it increasing weight but not mass.
<span>A large hole will form as a result of the volcano caving in. This can also be known as a caldera. The caldera is creating when the empty magma chamber of the volcano collapses.</span>
Answer:
B. the air pressure decreases
Explanation:
As elevation increases, there is less overlying atmospheric pressure mass, so that atmospheric pressure decreases with increasing elevaton.
