Protons, neutrons, and electrons<span> are the three main subatomic particles found in an atom.</span>
Answer: c) 90 m/s
Explanation:
Given
Invest velocity, v1 = 250 m/s
Inlet specific enthalpy, h1 = 270.11 kJ/kg = 270110 J/kg
Outlet specific enthalpy, h2 = 297.31 kJ/kg = 297310 J/kg
Outlet velocity, v2 = ?
0 = Q(cv) - W(cv) + m[(h1 - h2) + 1/2(v1² - v2²) + g(z1 - z2)]
0 = Q(cv) + m[(h1 - h2) + 1/2(v1² - v2²)]
0 = [(h1 - h2) + 1/2(v1² - v2²)]
Substituting the values of the above, we get
0 = [(270110 - 297310) + 1/2 ( 250² - v²)
0 = [-27200 + 1/2 (62500 - v²)]
27200 = 1/2 (62500 - v²)
54400 = 62500 - v²
v² = 62500 - 54400
v² = 8100
v = √8100
v = 90 m/s
The concept of a black hole seem reasonable to me because of its valid and authentic evidences.
<h3>What are the causes, characteristics, and major features of black holes?</h3>
A black hole is a region in space where light is unable to escape due to strong gravitation force. The strong gravity is formed because matter has been pressed into a tiny space. This compression occurs at the end of a star's life. Some black holes are formed when a stars die.
So we can conclude that the concept of a black hole seem reasonable to me because of its valid and authentic evidences.
Learn more about black hole here: brainly.com/question/468699
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Answer:
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^9V
Explanation:
from V = kQ/r
Uncertainty in V is given by δV = V square root [ (δQ/Q)^2 + (δr/r)^2]
ΔV = V square root [ (ΔQ/Q)^2 + (Δr/r)^2] .....................(2)
Given that ; Q = 3.2042e−19 C, r = 0.08 m, ΔQ = 1.6021e−21 C, Δr = 0.005 m
Plugging the values given into equation (2)
from ΔV =(kQ/r) square root [ (ΔQ/Q)^2 + (Δr/r)^2]
ΔV = 9 x 10^9 x 3.2042e−19 / 0.08 square root [ (1.6021e−21/ 3.2042e−19)^2 + ( 0.005/0.08)^2]
ΔV = 360.47 x 0.06269 x 10^-10
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^-9V
Oh wait if what I said is wrong actually and now of what I'm telling you right now is really actually the answer... so when 108 grams of water at a temperature of 22.5c is mixed with 65.1 grams of water at an unknown temperature,the final temperature of the resulting mixture of 47.9c.
