Difference between text-talk novel and flash fiction?
1 answer:
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The density of the nugget is and is made of gold
Explanation:
The density of an object can be calculated as
where
d is the density
m is the mass
V is the volume of the object
We have to note that density of an object actually depends on the material the object is made of (therefore, two objects made of the same material can have different mass and different volume, but they have same density).
For the nugget in this problem, we have:
mass: m = 38 g
volume:
So, its density is
And by looking at the table, we see that this value corresponds approximately to the density of gold, so the nugget is made of gold.
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The magnitude of the average friction force exerted on the collar (F)= 8.641 N
<h3>How can we calculate the magnitude of the average friction force exerted on the collar?</h3>To calculate the magnitude of the average friction force exerted on the collar we are using the formula,
Here we are given,
k = The spring has a spring constant.
= 25.5 N/m.
= Final length of the spring .
=
= 1.591 m
= The initial length of the spring.
= 1.25−0.60
=0.65 m
y=The collar then travels downward a distance.
= 1.80 m.
m= The mass of the collar.
=3.55 kg
= the velocity of the collar.
= 3.39 m/s.
g = The acceleration due to gravity.
= 9.81 m/s²
We have to calculate the magnitude of the average friction force exerted on the collar = F
Now we put the known values in the above equation, we get;
Or,
Or, F= 8.641 N
From the above calculation we can conclude that,
The magnitude of the average friction force exerted on the collar (F)= 8.641 N
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Disclaimer: This question is incomplete in the portal. Here is the complete question.
Question:
The 3.55 kg collar shown below is attached to a spring and released from rest at A. The collar then travels downward a distance of y = 1.80 m. The spring has a spring constant of k = 25.5 N/m. The distance a is given as 1.25 m. The datum for gravitational potential energy is set at the horizontal line through A and B. Determine the magnitude of the average friction force exerted on the collar when the velocity of the collar at c is 3.39 m/s and the spring has an unstretched length of 0.60 m .
Answer:
T=1.384×10⁶seconds
Explanation:
Given data
p (Intensity)=1.30 kw/m²
E (Energy)=1.8×10⁹ J
A (Area)=1.00 m²
T (Time required)=?
Solution
E=PT ................eq(i)
where E is energy
P is radiation power
T is time
Radiating Power is given as
P=pA
Where p is intensity
A is Area
Put P=pA in eq(i) we get
E=pAT
T=E/pA
Answer:
Explanation:
The formula for the force exerted between two charges is
where k is the Coulomb constant.
The charges are identical, so we can write the formula as