Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
She would have a total of 40 stamps.
Answer:
N = 14348907
Step-by-step explanation:
81^5 = 3486784401
3486784401/243 = 14348907
Double Check
3486784401 / 14348907=243
So N = 14348907.
Answer:
Step-by-step explanation:
A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?
Answer:
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Step-by-step explanation:
