All categories

3 years ago

What are the answers for page 501

Mathematics

1 answer:

expeople1 [14]3 years ago

6 0

I'm so sorry for not answer but which grade and what workbook is it?

You might be interested in

L need help with this

soldi70 [24.7K]

Answer:

$24.11

Step-by-step explanation:

Let the cost of the present be c.

Then (3/4)c = $18.33.

To isolate (solve for) c, mult. both sides of this equation by (4/3):

(4/3)(3/4)c = (4/3)($18.33), or

c = $24.11

5 0

3 years ago

A baker divides 21.4 pounds of flour equally between five recipes. How much flour did the bakery use for each recipe?

worty [1.4K]

Answer:

4.28 per recipe

Step-by-step explanation:

21.4 divided by 5 = 4.28 per recipe

4 0

2 years ago

Read 2 more answers

The graph h = −16t^2 + 25t + 5 models the height and time of a ball that was thrown off of a building where h is the height in f

Thepotemich [5.8K]

Answer:

part 1) 0.78 seconds

part 2) 1.74 seconds

Step-by-step explanation:

step 1

At about what time did the ball reach the maximum?

Let

h ----> the height of a ball in feet

t ---> the time in seconds

we have

$h(t)=-16t^{2}+25t+5$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the time when the ball reach the maximum

Find the vertex

Convert the equation in vertex form

Factor -16

$h(t)=-16(t^{2}-\frac{25}{16}t)+5$

Complete the square

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+5+\frac{625}{64}$

$h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}\\h(t)=-16(t^{2}-\frac{25}{16}t+\frac{625}{1,024})+\frac{945}{64}$

Rewrite as perfect squares

$h(t)=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

The vertex is the point $(\frac{25}{32},\frac{945}{64})$

therefore

The time when the ball reach the maximum is 25/32 sec or 0.78 sec

step 2

At about what time did the ball reach the minimum?

we know that

The ball reach the minimum when the the ball reach the ground (h=0)

For h=0

$0=-16(t-\frac{25}{32})^{2}+\frac{945}{64}$

$16(t-\frac{25}{32})^{2}=\frac{945}{64}$

$(t-\frac{25}{32})^{2}=\frac{945}{1,024}$

square root both sides

$(t-\frac{25}{32})=\pm\frac{\sqrt{945}}{32}$

$t=\pm\frac{\sqrt{945}}{32}+\frac{25}{32}$

the positive value is

$t=\frac{\sqrt{945}}{32}+\frac{25}{32}=1.74\ sec$

8 0

3 years ago

Examine the following diagram:<br><br><br> What is the measure of ∠DBC?

gtnhenbr [62]

1 + 1 = 2 - 1 = 1 hope this helps.

3 0

3 years ago

Read 2 more answers

4. What’s the answer to this question please

s2008m [1.1K]

Answer:

Step-by-step explanation:

8 0

3 years ago