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sweet-ann [11.9K]
2 years ago
13

What is the LCM of 4 and 18

Mathematics
1 answer:
Verizon [17]2 years ago
4 0

Answer:

36

Explanation:

Multiples of 4 are:

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64,...

Multiples of 18 are:

18, 36, 54, 72, 90, 108, 126, 144,...

The least common multiple of 4 and 18 is 36.

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Acar traveled 50 miles in 40 minutes. Assume that the car will continue at this constant
zalisa [80]

Answer:

Would 50 divided by 40 work?

Step-by-step explanation:

7 0
3 years ago
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Use the box plots comparing the number of boy dogs and number of girl dogs attending doggy daycare each day for a month to answe
satela [25.4K]

The boxplots 1 and 2 represent the distribution of data using a five number summary for the male and the female attendance

<h3>(a) The IQR of the male's data</h3>

The first box plot represents the male's boxplot.

So, we have:

  • Upper quartile (Q3) = 14
  • Lower quartile (Q1) = 2

The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

<h3>(b) The difference in the median values</h3>

From the first and second boxplots, we have:

  • Median male = 10
  • Median female = 18

The difference (d) between these values is

d = 18 - 10

d = 8

So: the difference between the median values of each data set is 8

<h3>(c) The distribution of data</h3>

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

  • Male's data: presence of an outlier - use median
  • Female's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

<h3>(d) Reason for outliers</h3>

A possible reason for outliers is sampling problems

Read more about boxplots at:

brainly.com/question/26392028

#SPJ1

5 0
3 years ago
Read 2 more answers
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
Arada [10]

Answer:

The number of bacteria at initial = 187

Step-by-step explanation:

Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.

\frac{dN}{dt} = k N

\frac{dN}{N}  = k dt

Integrating both side we get

㏑ N = k t + C ------- (1)

Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.

⇒ ㏑ 500 = 3 k + C -------- (2)

⇒ ㏑ 5000 = 10 k + C ------ (3)

⇒ ㏑ 5000 -  ㏑ 500 = 7 k

⇒ ㏑\frac{5000}{500} = 7 k

⇒  ㏑ 10 = 7 k

⇒ k = 0.329

Put this value of k in equation (2),

⇒ ㏑ 500 = 3 × 0.329 + C

⇒ C = 5.23

Put this value of C in equation 1 we get,

⇒ ㏑ N = k t + 5.23

Initially when t = 0 , then

⇒ ㏑ N = 5.23

⇒ N =  187

Thus the number of bacteria at initial = 187

8 0
4 years ago
Solve the math problem
luda_lava [24]

Answer: a) y=-29x-20 b) y=3/5x-18

Step-by-step explanation:

a) m = (-49-38)/(1 - (-2)) = -87/3 = -29

y=-29x+b --> Substitute (1,-49) as a point

(-49)=-29(1)+b

-49=-29+b

-b=-29+49

b=-20

Therefore, the equation of the line is y=-29x-20

b) m = (-18-(-9)/(0-15)) = -9/-15 = 3/5

The y-intercept is (0,-18) as it's where the line intersects the y-axis and x equals 0

Therefore, the equation of the line is y=3/5x-18

4 0
3 years ago
What is the value of x?
kari74 [83]

Answer:

4

Step-by-step explanation:

I took the quiz, here's proof

4 0
3 years ago
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