Answer:
50 N ( left)
Explanation:
Given data:
The force on right side = 450 N
The force on left side = 500 N
Net force = ?
Solution:
F (net) = 500 N - 450 N
F (net) = 50 N ( left)
For the given molecule, we are asked to give-
- The electron configuration of an isolated B atom
- The electron configuration of an isolated F atom
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
- valence orbitals, if any, remain unhybridized on the B atom.
- The electron configuration of an isolated B atom:
as atomic number of B is 5
electronic configuration will be [He] 2s² 2p¹
- The electron configuration of an isolated F atom:
as atomic number of F is 9
electronic configuration will be [He] 2s² 2p5
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.
as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.
- valence orbitals, if any, remain unhybridized on the B atom will be 1
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Answer
Weathering and erosion are two processes of which sedimentary rocks are broken down and carry away existing rocks.
Explanation:
Answer: The concentration of 
ions in the resulting solution is 1.16 M.
Explanation:
To calculate the molarity of the solution after mixing 2 solutions, we use the equation:
where,
are the n-factor, molarity and volume of the 
are the n-factor, molarity and volume of the 
We are given:
Putting all the values in above equation, we get
The concentration of ions in the resulting solution will be same as the molarity of solution which is 1.16 M.
Hence, the concentration of ions in the resulting solution is 1.16 M.
Answer:
Explanation:
412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)
130 ATP from the oxidation of palmitate
22 ATP from the oxidation of glycerol
Altogether 130 + 22 = 412 ATP will be produced.
Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.
When 51 carbons can produce 412 ATPs
Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.
This shows that ATP yield per carbon often oxidized will be 8.1 ATPs
Now we will see the ATP yield in the case of glucose.
Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs
When 6 carbons can yield 38 ATPs
Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.
So, ATP yield per carbon in case of glucose will be 6.33 ATPs
