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ValentinkaMS [17]
2 years ago
6

Which parts of sedimentary rock formation include the breakdown and carrying away of existing rock? Check all that apply.

Chemistry
1 answer:
stiks02 [169]2 years ago
3 0

Answer

Weathering and erosion are two processes of which sedimentary rocks are broken down and carry away existing rocks.

Explanation:

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Hellpppppp! Please!!!!
lana [24]

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3 years ago
Compared with ionic compounds, covalent compounds
Soloha48 [4]
They have low boiling points
5 0
3 years ago
If the CaCO3 weighed 983 g and the CaO weighed 551 g, how many grams of CO2 were formed in the reaction?
stira [4]

Answer:

The answer to your question is 432 g of CO₂

Explanation:

Data

CaCO₃  = 983 g

CaO = 551 g

CO₂ = ?

Balanced reaction

                               CaCO₃ (s)   ⇒   CaO (s)   +  CO₂ (g)

This reaction is balanced, to solve this problem just remember the Lavoisier Law of conservation of mass that states that the mass of the reactants is equal to the mass of the products.

                    Mass of reactants = Mass of products

                    Mass of CaCO₃   = Mass of CaO + Mass of CO₂

Solve for CO₂

                    Mass of CO₂  = Mass of CaCO₃ - Mass of CaO                    

                     Mass of CO₂ = 983 g - 551 g

Simplification

                     Mass of CO₂ = 432 g                        

         

5 0
2 years ago
If is found that 24.68 mL of .1165 M NaOH is needed to titrate .2931 g of an unknown acid to the phenolphthalein end point. Calc
Lemur [1.5K]

Answer: The equivalent mass of the acid is 83.16 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}  

Molarity of NaOH solution = 0.1165 M

Volume of NaOH solution = 24.68 mL = 0.02468 L

Putting values in equation 1, we get:

\text{Moles of} NaOH={0.1165M}\times{0.02468L}=2.875\times 10^{-3}moles=2.875\times 10^{-3}geq    

( as acidity of NaOH is 1)

For end point:  gram equivalents of acid =  gram equivalents of base = 2.875\times 10^{-3}

Mass of acid=gram equivalents\times {\text {Equivalent mass}}

0.2391=2.875\times 10^{-3}\times {\text {Equivalent mass}}

{\text {Equivalent mass}}=83.16g

Thus equivalent mass of the acid is 83.16 grams

5 0
3 years ago
What is the volume(in liters at stp) of 2.50 mil of carbon monoxide
NeTakaya

The volume of one mole of substance is 22.4 L

8 0
3 years ago
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