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ddd [48]
1 year ago
13

Consider the molecule BF3. (a) What is the electron config- uration of an isolated B atom? (b) What is the electron con- figurat

ion of an isolated F atom? (c) What hybrid orbitals should be constructed on the B atom to make the B–F bonds in BF3? (d) What valence orbitals, if any, remain unhybrid- ized on the B atom in BF3?
Chemistry
1 answer:
anzhelika [568]1 year ago
8 0

For the given molecule, we are asked to give-

  1. The electron configuration of an isolated B atom
  2. The electron configuration of an isolated F atom
  3. Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
  4. valence orbitals, if any, remain unhybridized on the B atom.
  • The electron configuration of an isolated B atom:

as atomic number of B is 5

electronic configuration will be [He] 2s² 2p¹

  • The electron configuration of an isolated F atom:

as atomic number of F is 9

electronic configuration will be  [He] 2s² 2p5

  • Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.

as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.

  • valence orbitals, if any, remain unhybridized on the B atom will be 1

To know more about hybrisisation:

brainly.com/question/23038117

#SPJ4

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<u>Answer:</u>

<u>For a:</u> The mass of acetic anhydride needed is 73.91 grams.

<u>For b:</u> The theoretical yield of aspirin is 130.43 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}   .....(1)

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Given mass of salicylic acid = 1.00\times 10^2g=100g

Molar mass of salicylic acid = 138.121 g/mol

Putting values in equation 1, we get:

\text{Moles of salicylic acid}=\frac{100g}{138.121g/mol}=0.724mol

For the given chemical reaction:

C_7H_6O_3+C_4H_6O_3\rightarrow C_9H_8O_4+CH_3COOH

By stoichiometry of the reaction:

1 mole of salicylic acid reacts with 1 mole of acetic anhydride.

So, 0.724 moles of salicylic acid will react with = \frac{1}{1}\times 0.724=0.724mol of acetic anhydride.

Now, to calculate the mass of acetic anhydride, we use equation 1:

Moles of acetic anhydride = 0.724 moles

Molar mass of acetic anhydride = 102.09 g/mol

Putting values in equation 1, we get:

0.724mol=\frac{\text{Mass of acetic anhydride}}{102.09g/mol}\\\\\text{Mass of acetic anhydride}=73.91g

Hence, the mass of acetic anhydride needed is 73.91 grams.

  • <u>For b:</u>

By stoichiometry of the reaction:

1 mole of salicylic acid is producing 1 mole of aspirin.

So, 0.724 moles of salicylic acid will produce = \frac{1}{1}\times 0.724=0.724mol of aspirin.

Now, to calculate the mass of aspirin, we use equation 1:

Moles of aspirin = 0.724 moles

Molar mass of aspirin = 180.158 g/mol

Putting values in equation 1, we get:

0.724mol=\frac{\text{Mass of aspirin}}{180.158g/mol}\\\\\text{Mass of aspirin}=130.43g

Hence, the theoretical yield of aspirin is 130.43 grams.

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