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Leokris [45]
2 years ago
9

After 1 min, three radioactive nuclei remain from an original sample of six. Is it valid to conclude that t₁/₂ equals 1 min? Is

this conclusion valid if the original sample contained 6X10¹² nuclei and 3X10¹²remain after 1 min? Explain.
Chemistry
1 answer:
Harrizon [31]2 years ago
7 0

Three of them may have decayed more quickly or more slowly than they should have according to the likelihood at that particular moment. However, suppose we have a lot of radioactive new Clyde's, say six times 10 to the 12, and we have three times 10 to the 12 in a minute. The rate may then be averaged out because there are a sufficient number of radioactive new Clyde's. Furthermore, we can say with confidence that the half life is one minute.

<h3>What is radioactivity?</h3>

Radioactivity, as its name suggests, is the act of generating radiation without any external cause. An atomic nucleus that is unstable for whatever reason does this by "wanting" to give up some energy in order to change its configuration to one that is more stable. Modern physics spent a lot of time in the first half of the 20th century figuring out why this occurs, which led to a pretty solid understanding of nuclear decay by 1960. A nucleus with too many neutrons will produce a negative beta particle, which will convert one of the neutrons into a proton. A nucleus with too many protons will emit positrons, which are positively charged electrons that turn protons into neutrons.

To know more about radioactivity:

brainly.com/question/1770619

#SPJ4

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What volume of 3.00 M HCl will form a solution with an acidic pH when mixed with 100 mL of 3.00 M NaOH
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<u>Answer:</u> The volume of acid should be less than 100 mL for a solution to have acidic pH

<u>Explanation:</u>

To calculate the volume of acid needed to neutralize, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH

We are given:

n_1=1\\M_1=3.00M\\V_1=?mL\\n_2=1\\M_2=3.00M\\V_2=100mL

Putting values in above equation, we get:

1\times 3.00\times V_1=1\times 3.00\times 100\\\\V_1=\frac{1\times 3.00\times 100}{1\times 3.00}=100mL

For a solution to be acidic in nature, the pH should be less than the volume of acid needed to neutralize.

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