Ask question

Ask question

All categories

1 year ago

7

What method could I use to test this hypothesis? If the mass and the volume of and object are known, then its density can be cal

culated dividing the object's mass by its volume.

1 answer:

Nitella [24]1 year ago

7 0

Answer:

The scientific method

Explanation:

You might be interested in

An atom that has a negative four charge will have which of the following? Question 1 options: 4 more protons than electrons An e

Lilit [14]

Electrons: negative charge
Protons: positive charge
Neutrons: negative charge

The atom would have to have more electrons than protons

Hope this helps :)

3 0

2 years ago

Positive charge Q is distributed uniformly along the x-axis fromx=0 to x=a. A positive point charge q is located on the positive

dybincka [34]

Answer:

a. b- x= y

dx = -dy

b. F = $\frac{-kQqi}{r (a+r)}$

c. F = $\frac{-kQqi}{r^{2} }$

Explanation:

a. x components:

$dE = \frac{kdq}{(a+r-x^{2}) } \\$

= $\frac{kQdx}{(a(a+r-x)^2}$

Integrating and solving gives:

b- x= y

dx = -dy

b. the force is given by the equation derived from (a.):

F = $\frac{-kQqi}{r (a+r)}$

c. Given that r>>a, the expression becomes:

F = $\frac{-kQqi}{r^{2} }$

Explanation:

When the size of the charge distribution is less than the distance to the deviation point of the charge then the charge distribution would produce the same effect such as a linear charge.

6 0

3 years ago

A circular wire loop of radius 15.0 cm carries a current of 2.60

Korolek [52]

Part (a): Magnetic dipole moment

Magnetic dipole moment = IA, I = Current, A = Area of the loop
Then,
Magnetic dipole moment = 2.6*π*0.15^2 = 0.184 Am^2

Part (b): Torque acting on the loop
T = IAB SinФ, where B = Magnetic field, Ф = Angle
Then,
T = Magnetic dipole moment*B*SinФ = 0.184*12*Sin 41 = 1.447 Nm

5 0

3 years ago

NEED HELP ASAP WILL MARK BRAINLIEST.

-Dominant- [34]

G is the answer for apex vs / Chehhhh

3 0

2 years ago

A student has a weight of 655 N. While riding a roller coaster they seem to weigh 1.96x 103 N at the bottom of a dip that has a

Nadya [2.5K]

Answer:

The speed of the roller coaster at this point is 18.74 m/s.

Explanation:

Given that,

Weight of the student, W = 655 kg

Weight of the roller coaster, $F=1.96\times 10^3\ N$

Radius of the roller coaster, r = 18 m

At the bottom of the loop, the weight of the roller coaster us given by :

$F=W+\dfrac{mv^2}{r}$

If m is the mass of the roller coaster,

$W=mg$

$m=\dfrac{W}{g}$

$m=\dfrac{655}{9.8}$

m = 66.83 kg

So,

$F=W+\dfrac{mv^2}{r}$

$v=\sqrt{\dfrac{(F-W)r}{m}}$

$v=\sqrt{\dfrac{(1.96\times 10^3-655)\times 18}{66.83}}$

v = 18.74 m/s

So, the speed of the roller coaster at this point is 18.74 m/s. Hence, this is the required solution.

4 0

3 years ago

Read 2 more answers