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lilavasa [31]
2 years ago
10

Place a pencil or pen in front of you on the surface that you are working on. In one paragraph, using your own words, describe t

hree different forces that are currently acting on your writing utensil, despite the fact that it is currently motionless. (Hint: Remember that the pencil is made of atoms and atoms are made of protons, neutrons, and electrons).
Physics
1 answer:
Ede4ka [16]2 years ago
4 0

Answer:

READ THIS FIRST!!!

I am not going to right the parragraph (it says to use your own words, they could trace it back to me if you use my words, and you would get it trouble).

But I will tell you the forces acting on the pencil:

Gravity (pulls on the pencil)

Your hand (pushing it up canceling out gravity)

And the electromagnetic force (holding the thing together)

Hope it helped,

Have a good day

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The older, geocentric model of the solar system placed the__________ at the center. Today's heliocentric model places the_______
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Which of the following statements is true regarding electromagnetic waves traveling through a vacuum?
kap26 [50]

Answer:

C. All waves have the same speed.

Explanation:

Wave equation is given as;

V = fλ

where;

V is the speed of the wave

f is the frequency of the wave

λ is the wavelength

The speed of the wave depends on both wavelength and frequency

The speed of the electromagnetic waves in a vacuum is 3 x 10⁸ m/s, this also the speed of light which is constant for all electromagnetic waves.

Therefore, the correct option is "C"

C. All waves have the same speed.

6 0
3 years ago
What is the gravitational potential energy of a projectile with mass 5 kg at<br> a height of 10 m?
zimovet [89]

Answer:

<h2>500 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

GPE = 5 × 10 × 10

We have the final answer as

<h3>500 J</h3>

Hope this helps you

3 0
3 years ago
To start a lawn mower, you must pull on a rope wound around theperimeter of a flywheel. After you pull the rope for 0.95 s, thef
Molodets [167]

Answer:

29.76245 rad/s², -117.80972 rad/s²

28.2743 rad/s

3.95833

Explanation:

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

\alpha = Angular acceleration

\theta = Angle of rotation

t = Time taken

Equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{4.5\times 2\pi-0}{0.95}\\\Rightarrow \alpha=29.76245\ rad/s^2

Angular acceleration during speed up is 29.76245 rad/s²

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\frac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\frac{0-4.5\times 2\pi}{0.24}\\\Rightarrow \alpha=-117.80972\ rad/s^2

Angular acceleration during spin down is -117.80972 rad/s²

Angular speed is given by

\omega=2\pi 4.5=28.2743\ rad/s

Maximum angular speed reached by the flywheel is 28.2743 rad/s

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=0\times t+\frac{1}{2}\times 29.76245\times 0.95^2\\\Rightarrow \theta=13.4303\ rad

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=2\pi 4.5\times 0.24+\frac{1}{2}\times -117.80972\times 0.24^2\\\Rightarrow \theta=3.39292\ rad

The ratio would be \dfrac{13.4303}{3.39292}=3.95833

3 0
3 years ago
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