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lilavasa [31]
3 years ago
10

Place a pencil or pen in front of you on the surface that you are working on. In one paragraph, using your own words, describe t

hree different forces that are currently acting on your writing utensil, despite the fact that it is currently motionless. (Hint: Remember that the pencil is made of atoms and atoms are made of protons, neutrons, and electrons).
Physics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

READ THIS FIRST!!!

I am not going to right the parragraph (it says to use your own words, they could trace it back to me if you use my words, and you would get it trouble).

But I will tell you the forces acting on the pencil:

Gravity (pulls on the pencil)

Your hand (pushing it up canceling out gravity)

And the electromagnetic force (holding the thing together)

Hope it helped,

Have a good day

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How do the three types of boundary's work together to keep the Earth at equilibrium?
Maurinko [17]
There are three types: divergent, convergent, and transform boundaries. I hope this helps.
8 0
3 years ago
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A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the
alexandr402 [8]

Answer:

r=6.05km/hr

z=59.1 degree to the horizontal

Explanation:

A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place

can be solved using pythagoras theorem

r^2=o^2+a^2

r^2=5.2^2+3.1^2

r^2=36.65

r=6.1km/hr is te birds velocity relative to the ground

tanz=5.2/3.1

z=tan^-1(5,2/3.1)

z=59.1 degree to the horizontal

7 0
3 years ago
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A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s
JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of  = 3.84 m/s

angle of the rain drop = 25°                      

tan θ = \dfrac{v}{u}                      

tan 25° = \dfrac{v}{3.84}                      

v =3.84 × tan 25°                      

v = 1.79 m/s                  

hence, the train is moving at the speed of v = 1.79 m/s

3 0
3 years ago
two billiard balls moving along the same line hit each other head-on. each has a mass of 0.220 kg; one has an initial velocity o
Tems11 [23]

Hi there!

Since the collision is elastic, we must also satisfy the following condition:

Ei = Ef, or:

KEi = KEf

Begin by writing an expression for momentum. (p = mv) Remember that one ball's direction is negative; in this instance, we can let the second ball be moving LEFT.

mv1 + mv2 = mvf1 + mvf2

0.220(1.84) + 0.220(-.530) = 0.220(vf1 + vf2)

0.2882/0.220 = vf1 + vf2

1.31 = vf1 + vf2

Now, we can express this as a conservation of energy:

1/2mv1² + 1/2mv2² = 1/2mvf1² + 1/2mvf2²

Plug in values and simplify:

0.403315 = 1/2m(vf1² + vf2²)

Simplify further:

3.6665 = vf1² + vf2²

Use the equation derived from momentum above and solve for one variable:

vf2 = 1.31 - vf1

Plug in this expression for vf2:

3.6665 = vf1² + (1.31 - vf1)²

Expand:

3.6665 = vf1² + 1.7161 - 2.62vf1 + vf1²

Simplify:

1.9504 = -2.62vf1 + 2vf1²

Solve for vf1 using a graphing calculator:

vf1 = -0.53 m/s or 1.84 m/s; we must figure out which one is correct.

Since v1 is heading to the right initially with a velocity of 1.84 m/s, we know that the ball's velocity could not have stayed the same in both magnitude and direction, so the final velocity must be -0.53 m/s.

Now, we can solve for the velocity of the other ball (initial of 0.53 m/s):

vf2 = 1.31 - (-0.53) = 1.84 m/s.

Now, you could have also made the connection that when two balls of the SAME MASS experience an ELASTIC collision, the velocities are simply "exchanged" from one to another. I just used this more "extensive" method to prove this.

7 0
3 years ago
A space vehicle is traveling at 5425 km/h relative to the Earth when the exhausted rocket motor (mass 4m) is disengaged and sent
lana66690 [7]

Answer:

V_{cE}=1489m/s

Explanation:

Given data

Space vehicle speed=5425 km/h relative to earth

The rocket motor speed=81 km/h  and mass 4m

The command has mass m

From the conservation of momentum as the system isolated

p_{i}=p_{f}\\

Since the motion in on direction we can drop the unit vector direction

MV_{i}=4mV_{mE}+mV_{CE}

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.

The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

V_{mE}=V_{mc}+V_{cE}

Where Vmc is the velocity of motor relative to command

This yields

5mV_{i}=4m(V_{mc}+V_{cE})+mV_{cE}\\5V_{i}=4V_{mc}+5V_{cE}

Substitute the given values

V_{cE}=\frac{5V_{i}-4V_{mc}}{5}\\ V_{cE}=5425*\frac{1000}{60*60}(m/s)-\frac{4}{5}*81\frac{1000}{60*60}(m/s)\\  V_{cE}=1489m/s

5 0
4 years ago
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