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ryzh [129]
2 years ago
5

Which of the following points is/are true for plasma?

Chemistry
2 answers:
Irina-Kira [14]2 years ago
6 0
The answer is 4. This is the answer because the first 3 are all correct
Likurg_2 [28]2 years ago
5 0

Answer:

4 all of the choices. the rest of the answers are correct so it's all of the choices

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How does the shape of an enzyme affect its function?
lutik1710 [3]

Each enzyme's active site is suitable for one specific type of substrate – just like a lock that has the right shape for only one specific key. Changing the shape of the active site of an enzyme will cause its reaction to slow down until the shape has changed so much that the substrate no longer fits.

5 0
4 years ago
Read 2 more answers
Part A Find ΔS∘ for the reaction between nitrogen gas and hydrogen gas to form ammonia: 12N2(g)+32H2(g)→NH3(g) Express your answ
inessss [21]

Answer:

\Delta S^{0} for the given reaction is -99.4 J/K

Explanation:

Balanced reaction: \frac{1}{2}N_{2}(g)+\frac{3}{2}H_{2}(g)\rightarrow NH_{3}(g)

\Delta S^{0}=[1mol\times S^{0}(NH_{3})_{g}]-[\frac{1}{2}mol\times S^{0}(N_{2})_{g}]-[\frac{3}{2}mol\times S^{0}(H_{2})_{g}]

where S^{0} represents standard entropy.

Plug in all the standard entropy values from available literature in the above equation:

\Delta S^{0}=[1mol\times 192.45\frac{J}{mol.K}]-[\frac{1}{2}mol\times 191.61\frac{J}{mol.K}]-[\frac{3}{2}mol\times 130.684\frac{J}{mol.K}]=-99.4J/K

So, \Delta S^{0} for the given reaction is -99.4 J/K

7 0
4 years ago
What information can a mineralogist learn from testing the mass and volume of a mineral?
Vesna [10]
Minerals can be identified by their physical characteristics. The physical properties of minerals are related to their chemical composition and bonding. Some characteristics, such as a mineral’s hardness, are more useful for mineral identification. Color is readily observable and certainly obvious, but it is usually less reliable than other physical properties.
6 0
3 years ago
Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I
Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, 1.077\times 10^9

Explanation :

First we have to calculate the moles of iron.

\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains 6.022\times 10^{23} number of iron atoms

So, 0.0519 mole of iron contains 0.0519\times 6.022\times 10^{23}=3.125\times 10^{22} number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = \frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}

Number of iron atoms are present in each red blood cell = \frac{3.125\times 10^{22}}{2.90\times 10^{13}}

Number of iron atoms are present in each red blood cell = 1.077\times 10^9

Therefore, the number of iron atoms present in each red blood cell are, 1.077\times 10^9

6 0
3 years ago
if the central atom in a molecule is sp3 hybridized, how many different electronic geometries can it have?
jekas [21]

Tetrahedral molecular geometry is the only one that can exist for sp3 hybridized center atoms.

<h3>Which chemical contains an sp3 hybridized central atom?</h3>
  • An atom that is bound and a nonponding pair of electrons are the two different kinds of electron domains.All bonded atoms count as one electron domain on the center atom, regardless of whether they are connected by a single, double, or triple bond.
  • There are five fundamental geometries for electron domains. The core oxygen atom in the water molecule has six valence electrons.The 6 valence electrons of oxygen are arranged in hybridized sp3 orbitals, resulting in 2 paired and 2 free electrons.
  • One s orbital and three p orbitals combine to generate four sp3 orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp3 hybridization.
  • An example of CO2 can be used to illustrate how lone pairs of electrons make up an SP3 hybrid orbital.We are only able to count bond pairs or lone bonds.

To learn more about sp3 refer

brainly.com/question/28359475

#SPJ4

6 0
1 year ago
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