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Arada [10]
3 years ago
9

What is the result of adding 2.5 × 10³ and 3.5 × 10²?

Chemistry
2 answers:
Elanso [62]3 years ago
7 0

Answer:

A

Explanation:

It is correct please I hope it helps! :)

Dvinal [7]3 years ago
6 0
Jdjdjfng jdjdjfng fifth djdkgh djdkfg VJCHGf 123
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Fossil fuel consists of coal, oil, and natural gas that have been formed from the remains of plants and animals that died millio
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Answer:The sun

Explanation:

Coal and crude oil are made from the remains of plants and animals that died long ago. The primary energy source in an ecosystem is the sun. Plants take in energy from the sun to produce high energy molecules which are transferred along the food chain to animals. When these plants and animals die, the high energy molecules are now stored in fossil fuels. Recall that the molecules were formed using energy from the sun, therefore, the sun is the energy source from which the high energy molecules contained in fossil fuels are obtained.

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How many protons are in Calcium - 41?
EastWind [94]

Answer:

the correct answer to your question is 20

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Which metal is most likely to form more than one kind of positively charged ion? sodium (Na) barium (Ba) nickel (Ni) magnesium (
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Nickel most likely will, it's a transition metal
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Classify the following as a heterogeneous, homogeneous, or a pure substance:
Hunter-Best [27]

Answer:

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Explanation:

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8 0
2 years ago
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The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
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