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krok68 [10]
3 years ago
7

Read the scenario.

Chemistry
1 answer:
bezimeni [28]3 years ago
4 0

The chemical equation of the synthesis reaction of ammonia is

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

Explanation:

Molar ratio is the ratio of number of moles between any two elements in the reactants side or in between reactant and product side.

Like, in the present situation, it is stated that the molar ratio between hydrogen gas and nitrogen gas is 3 : 1. This means 3 number of hydrogen molecules and 1 number of nitrogen molecule are required to form the product ammonia.

Since, it is known that two hydrogen atoms will make a single hydrogen molecule, so 3 number of hydrogen molecules means, 3 H₂ is one of the reactant. Similarly, two nitrogen atoms can make a single nitrogen molecule, so N₂ is another reactant. Thus the two reactants are obtained as 3 H₂ and N₂.

Now, it is also stated that the molar ratio between ammonia (NH₃) and hydrogen gas (H₂) is 2 : 3. This means 2 number of ammonia molecules are present in the product side. And we know that 3 number of hydrogen molecules are present in the reactant side.

Thus, the chemical equation of the synthesis reaction of ammonia is

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

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3. Given 20g of Barium Hydroxide, how many grams of
anastassius [24]

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

Number\ of\ moles = \frac{Mass}{Molar\ mass}

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =\frac{20}{171.34}

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

Learn more on determining mass of reactant required here: brainly.com/question/11232389

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