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krok68 [10]
3 years ago
7

Read the scenario.

Chemistry
1 answer:
bezimeni [28]3 years ago
4 0

The chemical equation of the synthesis reaction of ammonia is

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

Explanation:

Molar ratio is the ratio of number of moles between any two elements in the reactants side or in between reactant and product side.

Like, in the present situation, it is stated that the molar ratio between hydrogen gas and nitrogen gas is 3 : 1. This means 3 number of hydrogen molecules and 1 number of nitrogen molecule are required to form the product ammonia.

Since, it is known that two hydrogen atoms will make a single hydrogen molecule, so 3 number of hydrogen molecules means, 3 H₂ is one of the reactant. Similarly, two nitrogen atoms can make a single nitrogen molecule, so N₂ is another reactant. Thus the two reactants are obtained as 3 H₂ and N₂.

Now, it is also stated that the molar ratio between ammonia (NH₃) and hydrogen gas (H₂) is 2 : 3. This means 2 number of ammonia molecules are present in the product side. And we know that 3 number of hydrogen molecules are present in the reactant side.

Thus, the chemical equation of the synthesis reaction of ammonia is

N₂ (g) + 3 H₂ (g) → 2 NH₃ (g)

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Answer:

91383 J

Explanation:

The equation of the reaction can be represented as:

\frac{1}{2} N_{2(g)}+\frac{1}{2} O_{2(g)}     ------>NO_{(g)}

Given that:

The standard enthalpy of formation of NO(g) is 91.3 kJ⋅mol−1 at 298.15 K.

The equation below shown the reaction between the enthalpy of reaction at a particular temperature to another.

\delta H^0__{R,T_2} = \delta H^0__{R,T_1} } + \int\limits^{T_2}_{T_1} {\delta C_p(T')} \, dT'

where:

\delta H^0__{R} = enthalpy of reaction

{\delta C_p(T')} = the difference in the heat capacities of the products and the reactants.

∴

\delta H^0__{R,435K} = \delta H^0__{R,298.15K} + \int\limits^{435}_{298.15} {\delta C_p(T')} \, dT'

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= 91300 J + (0.605 J.K⁻¹)(435-298.15)K

= 91382.79 J

\delta H^0__{R,435K} ≅ 91383 J

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