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Dmitrij [34]
3 years ago
8

At the end we stopped the distillation with some material left in the vial. Why is it considered unsafe to distill until dryness

?
Chemistry
1 answer:
kakasveta [241]3 years ago
8 0

Answer:

See the answer below

Explanation:

Distillation is a process of separating the contents of a liquid mixture by making use of the difference in the boiling temperatures of the components of the mixture. As the boiling point of each component is reached, it evaporates off and the vapor is condensed and collected to give a pure product.

<em>It is never advisable to distillate to dryness because allowing the content of the distilling flask to dry up can cause heat to damage the flask or in some extreme cases, cause unintended chemical reactions that might alter the outcome of the experiment or cause laboratory accident.</em>

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Dear friend,
How are you doing? I finally switched to my new school and it's been so hard adjusting. But I know I have a new chance at making new friends and memories. Also, I can learn new things, like interacting with new people and how to keep my anxiety low. I really miss us hanging out and how much we'd laugh and get in trouble at class. But i really hope to see you soon & that it hasn't gone terribly wrong for you since i left.
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8 0
2 years ago
A 0.1326 g sample of magnesium was burned in an oxygen bomb calorimeter. the total heat capacity of the calorimeter plus water w
Sladkaya [172]

Answer: Th enthalpy of combustion for the given reaction is 594.244 kJ/mol

Explanation: Enthalpy of combustion is defined as the decomposition of a substance in the presence of oxygen gas.

W are given a chemical reaction:

Mg(s)+\frac{1}{2}O_2(g)\rightarrow MgO(s)

c=5760J/^oC

\Delta T=0.570^oC

To calculate the enthalpy change, we use the formula:

\Delta H=c\Delta T\\\\\Delta H=5760J/^oC\times 0.570^oC=3283.2J

This is the amount of energy released when 0.1326 grams of sample was burned.

So, energy released when 1 gram of sample was burned is = \frac{3283.2J}{0.1326g}=24760.181J/g

Energy 1 mole of magnesium is being combusted, so to calculate the energy released when 1 mole of magnesium ( that is 24 g/mol of magnesium) is being combusted will be:

\Delta H=24760.181J/g\times 24g/mol\\\\\Delta H=594244.3J/mol\\\\\Delta H=594.244kJ/mol

4 0
3 years ago
How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?
Zielflug [23.3K]

Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Molarity x volume

Substitution

Number of moles = 1 x 0.75

Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

                          34.5 g of KCl ----------------  1 mol

                             x                  ----------------  0.75 moles

                            x = (0.75 x 34.5) / 1

                            x = 25.9 g of KCl

3 0
3 years ago
de The below to investigate the burning of a candle study it andwer the questions that following question . What would happen to
Eddi Din [679]

Answer:

When a candle burns, the hydrogen and carbon from the wax combine with the oxygen in the air to become carbon dioxide and water vapor. Most of the matter in the candle ends up as these two gases.

7 0
2 years ago
Which of the following measurements are listed in the proper mathematical relationship?(Select all that apply)
Igoryamba

The measurements which are listed in the proper mathematical relationship include:

  • PV=k
  • V/T=k
  • PV/T = k

<h3>What is a Constant?</h3>

This is used in mathematical expressions and has a constant value which doesn't change in expression.

Options A,B and C have the appropriate constants as pressure is usually multiplied by volume.

Read more about Constant here brainly.com/question/15989275

#SPJ1

8 0
1 year ago
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