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4 years ago

Ionic formula for ethanoate ion

1 answer:

4 0

Nomenclature and common formula. When part of a salt, the formula of the acetate ion is written as CH3CO2−, C2H3O2−, or CH3COO−. Chemists abbreviate acetate as OAc− or, less commonly, AcO−. Thus, HOAc is the abbreviation for acetic acid, NaOAc for sodium acetate, and EtOAc for ethyl acetate.

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Please answer in order the squares are numbered

insens350 [35]

Answer:

1 , 2 , 3 , 4 , 5

Explanation:

4 0

3 years ago

A block of ice sitting at 0 °C is completely melted by adding 584.5 J of heat to it. If the latent heat of fusion for ice is 334

Likurg_2 [28]

Answer:

mass of ice is 1.75

Explanation:

Using, the formula given in the question,

m = Q/HΔf.................. Equation 1

Where Q = Heat, m = mass of ice, HΔf = Latent heat of fussion of for ice.

From the question,

Given: Q = 584.5 J, HΔf = 334 J/g

Substitute these values into equation 2

m = 584.5/334

m = 1.75 kg.

Hence the mass of ice without unit is 1.75

7 0

3 years ago

Which of the following items is NOT a compound?

Ede4ka [16]

NaOH but you didnt give options

7 0

2 years ago

What volume of carbon dioxide is produced when 0.489 mol of calcium carbonate reacts completely according to the following react

Vilka [71]

Answer:

11.0L of carbon dioxide is produced

Explanation:

Balanced equation: $CaCO_{3}(s)\rightarrow CaO(s)+CO_{2}(g)$

According to balanced equation, 1 mol of $CaCO_{3}$ produces 1 mol of $CO_{2}$

So, 0.489 mol of $CaCO_{3}$ produces 0.489 mol of $CO_{2}$

Let's assume $CO_{2}$ behaves ideally.

So, $P_{CO_{2}}V_{CO_{2}}=n_{CO_{2}}RT$

where P is pressure, V is volume , n is number of moles, R is gas constant and T is temperature in kelvin

Plug-in all the values in the above equation-

$(1atm)\times V_{CO_{2}}=(0.489mol)\times (0.0821L.atm.mol^{-1}.K^{-1})\times (273K)$

or, $V_{CO_{2}}=11.0L$

So, 11.0L of carbon dioxide is produced

4 0

3 years ago

Rachel burns a 53 gram cracker under a soda can filled with 81.6 grams of water. She took the temperature of the water before sh

Anna11 [10]

Answer

Q=4479.8 cal

Procedure

To solve the problem you will need to use the specific heat formula

$Q=mc\Delta T$

Where;

Q=heat energy

m=mass

c=specific heat capacity

ΔT=change in temperature

Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.

$c_{water}=4.186\frac{J}{g\degree C}$

Substituting the values in our equation we have

$Q=mc\Delta T=81.6\text{ }g(4.186\frac{J}{g\degree C})(68.1-13.2)\degree C=18752.61\text{ }J$

Finally, transform the J to cal

$18752.61\text{ }J\frac{1\text{ }cal}{4.186\text{ }J}=4479.8\text{ cal}$

8 0

1 year ago