The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Dichlorine monoxide has the same structure like that of water. So, this is a polar molecule. For polar molecules, the dominant intermolecular force would be dipole-dipole forces. For HBr, there is a force between two oppositely charged ions, H⁺ and Br⁻. So, the dominant intermolecular force is electrostatic attraction.
C
a parasite is an organism that lives inside a host and benefits from taking away nutrients at the others expense
Answer:
90g of H2O
Explanation:
2H2 + O2 —> 2H2O
First, we calculate the molar masses of H2 And H20.
Molar Mass of H2 = 2g/mol
Mass conc of H2 from the balanced equation = 2 x 2 = 4g
Molar Mass of H2O = 2 + 16 = 18g/mol
Mass conc of H2O from the balanced equation = 2x18 = 36g
From the equation,
4g of H2 produced 36g of H2O
Therefore, 10g of H2 will be produce = (10x36)/4 = 90g of H2O
<span>The number next to the simbol of the element ions (as a superscript) means the number of charges of the ion. For example N (+),, where (+) is a superscript means that the charge of the ion is 1+. S(2-), where (2-) is a superscript, means that the charge of the ion is (2-). OH (-), where (-) is a superscript, means that the charge of OH ion is (1-) . </span>
