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2 years ago

8

6.Ocean water contains a mixture of salt & woter. It would be classified as?

1 answer:

wlad13 [49]2 years ago

5 0

Answer:

im pretty sure its: homogeneous mixture

Explanation:

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At 19 °C, the vapor pressure of pure ethanol is 40.0 mmHg.<br> What is the pressure in atm?<br> atm

m_a_m_a [10]

Answer:

0.05263158 atm

Explanation: mmHg to Atmosphere Conversion Example. Task: Convert 975 mmHg to atmospheres (show work) Formula: mmHg ÷ 760 = atm Calculations: 975 mmHg ÷ 760 = 1.28289474 atm Result: 975 mmHg is equal to 1.28289474 atm. This is an example for how i got the answer.

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2 years ago

Can someone give me a model that demonstrates the structure of polypropylene?

dem82 [27]

Answer:

look at the photo below

Explanation:

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2 years ago

Read 2 more answers

Balance the following H2 SO4 + NaOH ==== NaSO + H2O

katrin [286]

Answer:

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

Explanation:

H2SO4 + NaOH ---> Na2SO4 + H2O

Na1 ---> 2Na

H2SO4 + 2NaOH ---> Na2SO4 + H2O

2H + 2H = 4H ----> 2H

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

4O + 2O -----> 4O + 2O

4 0

3 years ago

Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) Given that ΔH° = 128.9 kJ/m

Ad libitum [116K]

Answer:

[tex]128^{o}C[/tex]minimum temperature will the reaction become spontaneous.

Explanation:

$\Delta G=\Delta H-T \Delta S$

From the given,

$\Delta G^{o}=33.1$

$\Delta H^{o}=128.9kJ/mol$

$Temperature\,change=25+273=98K$

$33.1=128.9-298 \Delta S$

$\Delta S=0.322kJ/mol.K$

$\Delta G=\Delta H-T \Delta S$

$0=128.9-T(0.322)=401K=218^{o}C$

Therefore, $128^{o}C$ minimum temperature will the reaction become spontaneous.

7 0

2 years ago

An aluminum cylinder has a radius of 3.2 cm and a length of 8.6 cm. What is the mass of the aluminum cylinder if aluminum has a

Hatshy [7]

Answer:

750g of Aluminum

Assuming 8.6 cm lenth is the height of the cylinder. The volume of a cylinder is: V = $\pi$ *r^2*h

V = 3.14cm x 10.24cm x 3.6cm

V = 280cm^3

Now density = mass/volume

2.7g/cm^3 = mass/280cm^3

2.7g/cm^3 x 280cm^3 = mass/<u>280cm^3</u> x <u>280cm^3</u>

= 750g of Aluminum

5 0

2 years ago