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liraira [26]
2 years ago
5

How many liters of a 4M solution can be made using 100 grams of LiBr?

Chemistry
1 answer:
REY [17]2 years ago
3 0

Answer:

volume = 0.288 L

Explanation:

To find the volume, you need to (1) convert grams LiBr to moles LiBr (via molar mass) and then (2) calculate volume (via molarity equation). It is important to arrange the ratios in a way tat allows for the cancellation of units (desired units in the numerator).

<u>(Step 1)</u>

Molar Mass (LiBr): 6.9410 g/mol + 79.904 g/mol

Molar Mass (LiBr): 86.845 g/mol

100 grams LiBr           1 mole
-----------------------  x  ------------------  =  1.15 moles LiBr
                                  86.845 g

<u>(Step 2)</u>

Molarity (M) = moles / volume (L)

4 M = 1.15 moles / volume

(4 M) x volume = 1.15 moles

volume = 1.15 moles / 4 M

volume = 0.288 L

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A chemistry graduate student is given 500. mL of a 0.20 M chloroacetic acid (HCH2ClCO2) solution. Chloroacetic acid is a weak ac
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Answer:

12 g of choloracetic acid

Explanation:

The buffer equilibrium is:

HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺

pka= -log ka =

Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]

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3,01 = 2,89 + log₁₀ [A⁻] / [HA]

1,318 = [A⁻] / [HA]

As molar concentration of chloroacetic acid (HA) is 0,20M

[A⁻] = 0,26 mol/L

The volume is 500 mL ≡ 0,5 L

0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:

0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>

<em></em>

I hope it helps!

3 0
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