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arlik [135]
4 years ago
8

To the nearest whole number how many moles are in 130 g sample of calcium metal?

Chemistry
1 answer:
lesantik [10]4 years ago
6 0
To convert grams to moles, we need the molar mass of the element or compound. remember you can determine the molar mass of a molecule by adding the atomic mass of each atom from the periodic table.

molar mass of Na= 23.0 g/ mol

130 g (1 mol Na/ 23.0 grams)= 5.65 moles or 6 moles.
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Chemistry student needs 15.0 g of painting for an experiment by consulting the CRC handbook of chemistry and physiology the stud
nalin [4]

Answer:

v = 23.96 cm³

Explanation:

Given data:

Mass = 15.0 g

Density = 0.626 g/cm³

Volume = ?

Solution:

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

v = m/d

v = 15 g / 0.626 g/cm³

v = 23.96 cm³

8 0
3 years ago
What is the answer and why
mario62 [17]
Nuclear power plant because that is a fission reaction and fusion would melt the power plant
4 0
3 years ago
Read 2 more answers
Will mark brainliest :) how many moles of a solute is present in 4.00 L of an 8.30 M solution?
andreev551 [17]

The answer is 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .

<h3>What is Molarity ?</h3>

Molarity is defined as the amount of solute (in moles)in per litre of solution.

It is also known as molar concentration of a solution , It is expressed in mol/l

\rm M =\dfrac{moles \;of\; solute}{Volume \;of \;solution} \\\\\\\rm M = \dfrac{n}{V} \\

We can rearrange this equation to get the number of moles:

n= M * V

The molarity of solution is 8.3 M and the volume given is 4 litres

the moles will be n = 8.30 * 4 = 33.2 moles

Therefore 33.2 moles of a solute is present in 4.00 L of an 8.30 M solution , Option A is correct .

To know more about molarity

brainly.com/question/2817451

#SPJ1

5 0
2 years ago
Could someone please care to explain what the answer is
polet [3.4K]

Calculate the percentage composition of Ca(MnO4)2.

<u>Firstly, we see how many atoms are there for each element in the formula</u>.

Ca= 1 atom

Mn= 2 atoms

O= 8 atoms

<u>Next, we are going to consult our periodic table for the atomic mass of each element.</u>

Ca= 40

Mn= 55

O= 16

Then, we have to find the molar mass for the compound..

Here is the formula for calculating molar mass of an element:

Molar Mass= ( no. of atoms of the element × atomic mass of the element)

Now, we have to calculate the atomic mass of the compound. So using the molar mass formula for an element, we calculate the molar mass for each element then we sum up their molar masses to get the compounds molar mass.

Molar mass (Ca)= 1× 40

(Ca)= 40

Molar mass (Mn)=2×55

(Mn)= 110

Molar mass (O)= 8×16

(O)= 128

Now: Molar mass( compound)= (Ca)+(Mn)+(O)

= 40+ 110 128

= 278

This is everything we need to calculate our percentage composition for each element..

* The example says to find the percentage composition for Ca. So we only find for Ca, Which is already done using the formula and the answer is 14.39%.

To prove that your answer is correct, find the percentage composition for Mn and O as well. Then you add up their percentage compositions.

If you do and you get 100 as your answer, then your percentage compositions are correct.

Why don't you try finding the percentage composition for Mn and O, then add up all the three percentage compositions. If you 100 as their sum, then your percentage composition for each of the elements are correct.

6 0
3 years ago
What is oxidation number​
MariettaO [177]

Antimony also forms trihalides and pentahalides, such as SbF3 , where its oxidation state is +3, and SbF5 , where its oxidation state is +5

7 0
3 years ago
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