And..............I dont think you wrote the whole question
Answer:
5 cm
Explanation:
We are given that,
The density of metal = 8 g/cm^3
The Mass of the Solid Cube = Mass of the metal = 1 kg = 1000 g
We know that,
Density = Mass / Volume
8 = 1000 / V
Hence, as the volume of the solid cube is 125 cm^3, its side will be the volume's cube root which is 5 cm
Answer;
-Period
Explanation;
-Properties of elements within a period on the periodic table change in a predictable way from one side of the table to the other. A period in the periodic table is a horizontal row. All elements in a row have the same number of electron shells.
-Elements in the same period have the same number of electron shells; moving across a period, elements gain electrons and protons and become less metallic.This arrangement reflects the periodic recurrence of similar properties as the atomic number increases.
Answer:
A
A. Energy is lost when machines don't work right.
Answer:
The magnitude of the field is 8.384×10^-4 T.
Explanation:
Now, i start solving this question:
First, convert the potential difference(V) 2 kv to 2000 v.
As, we have the final formula is qvB = mv^2/r. It came from the centripetal force and the magnetic force and we know that these two forces are equal. When dealing with centripetal motion use the radius and not the diameter so
r = 0.36/2 = 0.18 m.
As, we are dealing with an electron so we know its mass is 9.11*10^-31 kg and its charge (q) is 1.6*10^-18 C.
We can solve for its electric potential energy by using ΔU = qV and we know potential energy initial is equal to kinetic energy final so ΔU = ΔKE and kinetic energy is equal to 1/2mv^2 J.
qV = 1/2mv^2
(1.6*10^-19C)(2000V) = (1/2)(9.11*10^-31kg) v^2
v = 2.65×10^7 m/s.
These all above steps we have done only for velocity(v) because in the final formula we have 'v' in it. So, now we substitute the all values in that formula and will find out the magnitude of the field:
qvB = mv^2/r
qB = mv/r
B = mv/qr
B = (9.11*10^-31 kg)(2.65×10^7 m/s) / (1.6*10^-19 C)(0.18 m)
Hence, B = 8.384*10^-4 T.
