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Lyrx [107]
2 years ago
5

Hi! 6 questions, find the slope of the line through the given points, ty! They should be practice questions

Mathematics
1 answer:
denis23 [38]2 years ago
7 0

Answer:

3. undefined (vertical line)

4. 1

7. -4

8. 3

11. undefined (vertical line)

12. -1/3

Step-by-step explanation:

You can use the slope formula to calculate the slope which is (y2-y1)/(x2-x1)

3. (-4 - (-2)) /  (6-6)  denominator is 0 here so the slope is undefined (vertical line)

4. (7 - 1) / (-2 - (-4)) = 6 / 6 = 1

7. (1 - (-7)) / (2 - 4) = 8 / -2 = -4

8. (-1 - 5) / (0 -2 ) = -6 / -2 = 3

11. (3 - 0) / (-6 - (-6)) = 3 / 0 = undefined (vertical line

12. (2 - 3) / (-5 - (-2) = 1 / -3 = -1/3

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The water diet requires you to drink two cups of water every half hour from the time you get up until you go to bed, but otherwi
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Answer:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

Step-by-step explanation:

For this case we have the following info given:

Weight before diet 180 125 240 150  

Weight after diet 170 130 215 152

We define the random variable D = before-after and we can calculate the inidividual values:

D: 10, -5, 25, -2

And we can calculate the mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

And the deviation with:

s= \sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And after replace we got:

\bar D= 7, s_d = 13.638

And the confidence interval for this case would be given by:

\bar D \pm t_{\alpha/2} \frac{s_d}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1= 4-1=3

For the 95% of confidence the value for the significance is \alpha=0.05 and the critical value would be t_{\alpha/2}= 3.182. And replacing we got:

7-3.182 \frac{13.638}{\sqrt{4}}= -14.698

7+3.182 \frac{13.638}{\sqrt{4}}= 28.698

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