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1 year ago

Hi! 6 questions, find the slope of the line through the given points, ty! They should be practice questions

Mathematics

1 answer:

denis23 [38]1 year ago

7 0

Answer:

3. undefined (vertical line)

4. 1

7. -4

8. 3

11. undefined (vertical line)

12. -1/3

Step-by-step explanation:

You can use the slope formula to calculate the slope which is (y2-y1)/(x2-x1)

3. (-4 - (-2)) / (6-6) denominator is 0 here so the slope is undefined (vertical line)

4. (7 - 1) / (-2 - (-4)) = 6 / 6 = 1

7. (1 - (-7)) / (2 - 4) = 8 / -2 = -4

8. (-1 - 5) / (0 -2 ) = -6 / -2 = 3

11. (3 - 0) / (-6 - (-6)) = 3 / 0 = undefined (vertical line

12. (2 - 3) / (-5 - (-2) = 1 / -3 = -1/3

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Eddi Din [679]

Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

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The magnitude of vecor v is given to be 10. So we can write:

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2 years ago

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Alla [95]

Answer:

$\displaystyle y=-\frac{1}{2}x+4$

Step-by-step explanation:

Equation of a Line

We can find the equation of a line by using two sets of data. It can be a pair of ordered pairs, or the slope and a point, or the slope and the y-intercept, or many other combinations of appropriate data.

We are given a line

$y - 12 = 2x -8$

And are required to find a line perpendicular to that line. Let's find the slope of the given line. Solving for y

$y = 2x +4$

The coefficient of the x is the slope

$m=2$

The slope of the perpendicular line is the negative reciprocal of m, thus

$\displaystyle m'=-\frac{1}{2}$

We know the second line passes through (2,3). That is enough information to find the second equation:

$y-y_o=m'(x-x_o)$

$\displaystyle y-3=-\frac{1}{2}(x-2)$

Operating

$\displaystyle y=-\frac{1}{2}(x-2)+3$

Simplifying

$\displaystyle y=-\frac{1}{2}x+4$

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Answer:

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x=20

y=20

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2 years ago

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