Answer:
17 kJ
Explanation:
Calculation for the Calculate the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C.
Using this formula
q = mC∆T
Where,
q represent Energy
m represent Mass of substance=0.60kg=600g
C represent Specific heat capacity=2.44J·g−1K−1.
∆T represent change in Temperature=2.2°C to 13.7°C.
Let plug in the formula
q=(0.60 kg x 1000 g/kg)(2.44 J/gº)(13.7°C-2.2°C)
q = (600g)(2.44 J/gº)(11.5º)
q=16.836 kJ
q= 17 kJ (Approximately)
Therefore the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C will be 17 kJ
Answer:
34.8 moles of CO₂ are produced
Explanation:
This is the reaction:
1C₅H₁₂ + 8O₂ → 6H₂O + 5CO₂
Ratio is 1:5. We make a rule of three
1 mol of pentane can produce 5 moles of CO₂
Then, 6.96 moles of pentane may produce (6.96 .5) / 1 = 34.8 moles
(26) All atoms area...<span><span>with the number of protons equaling the number of electrons
</span>(27) </span>The particles that are found in the nucleus of an atom are...<span> protons and neutrons.
(28) </span>As a consequence of the discovery of the nucleus by Rutherford, which model of the atom is thought to be true?...<span>Protons. electrons, and neutrons are evenly distributed throughout the volume of the atom.
(29) </span>The nucleus of an atom is...<span>the central core and is composed of protons and neutrons</span>.
ideal gas law. but you are talking about moles of gas not miles
Answer:bromine , neon , helium , argon , lithium , beryllium
Explanation:
