7 moles of BaBr₂ produces 14 moles of KBr.
<u>Explanation:</u>
Given reaction is
BaBr₂ + K₂SO₄ → KBr + BaSO₄
It can be balanced by putting 2 in front of KBr as,
BaBr₂ + K₂SO₄ → 2 KBr + BaSO₄
From the above balanced equation, it was found that, 1 mole of Barium bromide required to produce 2 moles of KBr.
Now the molar ratio of BaBr₂ to KBr is written as 1 : 2.
In the same way, the molar ratio for 7 moles of BaBr₂, can be written as 7:14.
So 7 moles of BaBr₂ produces 14 moles of KBr.
