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VMariaS [17]
3 years ago
9

How many moles of KBr will be produced from 7 moles of BaBry? BaBr2+ K2SO4 → KBr +BaSO4

Chemistry
1 answer:
dalvyx [7]3 years ago
7 0

7 moles of BaBr₂ produces 14 moles of KBr.

<u>Explanation:</u>

Given reaction is

BaBr₂ + K₂SO₄ → KBr + BaSO₄

It can be balanced by putting 2 in front of KBr as,

BaBr₂ + K₂SO₄ → 2 KBr + BaSO₄

From the above balanced equation, it was found that, 1 mole of Barium bromide required to produce 2 moles of KBr.

Now the molar ratio of BaBr₂ to KBr is written as 1 : 2.

In the same way, the molar ratio for 7 moles of BaBr₂, can be written as 7:14.

So 7 moles of BaBr₂ produces 14 moles of KBr.

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Complete the acid–base equation for the dissolution of the following compound into liquid HF solvent. The relevant pKa values ar
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Answer:

The balanced chemical equation: NH₃ + 2 HF → NH₄⁺ + HF₂⁻

Explanation:

According to the Brønsted–Lowry acid–base theory, the acid- base reaction is a type of chemical reaction between the acid and base to give a conjugate acid and a conjugate base.

In this reaction, a Brønsted–Lowry acid loses a proton to form a conjugate base. Whereas, a Brønsted–Lowry base accepts a proton to form a conjugate acid.

Acid + Base ⇌ Conjugate Base + Conjugate Acid

The acid dissociation constant (Kₐ) <em>signifies the acidic strength of a chemical species.</em>

∵ pKₐ = - log Kₐ

Thus for a strong acid, Kₐ value is large and pKₐ value is small.

pKₐ (HF) = 3.2 → strong acid

pKₐ (NH₃) = 38 → weak acid

<u>The chemical reaction involved in the dissolution process:</u>

NH₃ + 2 HF → NH₄⁺ + HF₂⁻

In this acid-base reaction, the acid HF reacts with NH₃ base to give the conjugate base HF₂⁻ and conjugate acid NH₄⁺.

<u>HF (acid) donates a proton to form the conjugate base, HF₂⁻ ion. NH₃ (base) accepts a proton to form the conjugate acid. </u>

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