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kondor19780726 [428]
3 years ago
9

What is the chemical formula for hydrogen phosphate​

Chemistry
1 answer:
Anton [14]3 years ago
3 0

Answer:

Explanation:

The chemical formula for hydrogen phosphate​ is HPO₄²⁻

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Iron (III) oxide reacts with solid carbon in the followed reaction: 2Fe2O3(s) + 3C(s) → 4Fe(s) + 3CO2(g) What mass of Fe2O3 is n
Veseljchak [2.6K]

953.6 g of iron (III) oxide (Fe₂O₃)

Explanation:

We have the following chemical reaction:

2 Fe₂O₃ (s) + 3 C (s) → 4 Fe (s) + 3 CO₂ (g)

We calculate the number of moles of CO₂ by using the following formula:

pressure × volume = number of moles × gas constant × temperature

number of moles = (pressure × volume) / (gas constant × temperature)

number of moles of CO₂ = (2.1 × 100) / (0.082 × 300)

number of moles of CO₂ = 8.54 moles

Taking in account the chemical reaction we devise the following reasoning:

if         2 mole of Fe₂O₃ produces 3 mole of CO₂

then   X moles of Fe₂O₃ produces 8.54 mole of CO₂

X = (2 × 8.54) / 3 = 5.69 moles of Fe₂O₃

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of Fe₂O₃ = 5.69 × 160 = 953.6 g

Learn more about:

number of moles

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6 0
3 years ago
Read 2 more answers
Why do we call water the univeral salivnet
ankoles [38]
Water<span> is capable of dissolving a variety of different substances, which is why it is such a good </span>solvent. Water dissolves more than any other liquid, therefor we called it the Universal Solvent.
6 0
3 years ago
13. When a train car traveling at 4 m/s collides with a stationary train car, what happens to the momentum of the first train ca
Solnce55 [7]

Answer:

Momentum of first train car will reduce

Explanation:

When the moving care collides with the stationary car, it will increase the momentum of the stationary car. However, its own momentum will reduce.

It is so because the speed of the first train car will reduce after collision due to loss of energy in the collision while the stationary car may gain some momentum due to rise in velocity from zero (velocity at stationary position).

5 0
3 years ago
Calculate the enthalpy of the reaction below (∆Hrxn, in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g).
nalin [4]

The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE  for C≡O  = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

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7 0
1 year ago
Which source would be the most reliable to validate a claim?
Mekhanik [1.2K]

Answer:

In general, print publications with authors and listed sources tend to be reliable because they provide sources which readers can verify. Likewise, Web postings with a .gov (posted by the United States government) are both current and reliable.

Explanation:

4 0
3 years ago
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