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kykrilka [37]
2 years ago
10

A ball is thrown straight upward at 10 m/s. Ideally (no air resistance), the ball will return to the thrower's hand with a speed

of
Physics
1 answer:
xxMikexx [17]2 years ago
3 0

Answer:

The ball will return to the thrower's hand with a speed of 10 m/s

Explanation:

  • what is straight upward motion?

It is the motion when an object is projected upward, it moves in the opposite direction of the force of gravity.

The velocity is negative while the object moves up and positive while it moves downward due to upward motion.

Here,

A ball is thrown straight upward, u = 10 m/s

final velocity since ball momentarily stops at highest point, v= 0 m/s

According to Newton's 3rd equation of motion:

  • 2gh = V² - u²

where,

g = acceleration due to gravity = -9.8 m/s²

h = height

substituting the values,

2(-9.8)h = (0)² - (10)²

h = 100 / 19.6

h = 5.10 m/s

Now, we consider downward motion:

2gh = v² - u²

where,

g  = 9.8 m/s²

h = height = 5.10  m

v = return velocity of ball

u = 0 m/s

substituting the values,

2(9.8)(5.10 m) = V² - (0)²

V = √(99.96)

V = 9.99 m/s

V ≈ 10 m/s

Hence,

the ball will return to the thrower's hand with a speed of 10 m/s

Learn more about projectile upward motion here:

<u>brainly.com/question/11049671</u>

<u />

#SPJ4

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A young woman walks up 55 steps to the top of a water slide. She slides
navik [9.2K]

Answer:

potential energy PE = M g h

KE at bottom = 1/2 M V^2

Regardless of the slope of the slide the change in energy is the same

1/2 V^2 = g h

V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s

Perhaps the question says that h = 55 * .1 = 5.5 m

Then V = (2 * 9.8 * 5.5) = 10.4 m/s

5 0
2 years ago
What makes astronomers think that impact rates for the Moon must have been higher earlier than 3.8 billion years ago?
dexar [7]

There is strong evidence indicating that 3.8 billion years ago there was a higher impact rate. This deduction starts from comparing the number of craters in the lunar highlands with those of the Mary. If this comparison is made, it will be observed that there are 10 times more craters in the highlands than in a similar area of Mary. It should be borne in mind that through radioactive dating processes the samples indicate that there is a slightly greater antiquity in the highlands than those of Maria. This allows us to deduce that if the impact rates had been constant, the highlands would have been 10 times older. They would have to be formed 38 billion years ago, long before the universe itself began.

Therefore one of the most obvious reasons is there are ten times more craters on the older highlands than the Younger Maria.

3 0
3 years ago
The length of a simple pendulum is 0.760 m, the pendulum bob has a mass of 365 grams, and it is released at an angle of 12.0o to
Allushta [10]

Answer:

0.572 Hz

Explanation:

given,

length of simple pendulum, l = 0.76 m

mass of the bob, m = 365 g = 0.365 Kg

angle made from the vertical, = 12°

frequency, f = ?

f = \dfrac{1}{2\pi}\sqrt{\dfrac{g}{L}}

f = \dfrac{1}{2\pi}\sqrt{\dfrac{9.8}{0.76}}

f = \dfrac{1}{2\pi}\times 3.59

       f = 0.572 Hz

The frequency at which pendulum vibrates is equal to 0.572 Hz

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4 years ago
Why aren't the electrons counted in the mass of an atom?
Radda [10]

Answer:

Explanation:

The mass of an electron is small compared to the neutron and proton, so it's negligible. It's like adding zero to a number.

3 0
3 years ago
A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t
Luda [366]

Answer:

Approximately 0.29\; {\rm m \cdot s^{-1}}.

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass m and velocity v is p = m\, v.

The momentum of the two trolleys before the collision would be:

  • 4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}.
  • 3\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m \cdot s^{-1}}.

Thus, the total momentum of the two trolleys right before the collision would be 2\; {\rm kg \cdot m \cdot s^{-1}}.

Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass m = 3\; {\rm kg} + 4\; {\rm kg} = 7\; {\rm kg}.

The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass m = 7\; {\rm kg} would continue to be v = 2\; {\rm kg \cdot m \cdot s^{-1}} shortly after the collision.

Rearrange the equation p = m\, v to find the velocity of the two trolleys combined:

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{2\; {\rm kg \cdot m \cdot s^{-1}}}{7\; {\rm kg}} \\ &\approx 0.29\; {\rm m \cdot s^{-1}}\end{aligned}.

6 0
2 years ago
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