Answer:
repulsion force es R = 5,224 10⁻³ N
Explanation:
We use Newton's second law to add forces, the elective force is repulsive because the asteroids have the same type of charge and gravitational force is always attractive.
Gravitational force
Fg = G m1 m2 / r²
Fg = 6,673 10⁻¹¹ 5.7 10⁴ 5.5 10⁴/190²
Fg = 5,795 10⁻⁶ N
Electric force
Fe = k q1 q2 / r²
Fe = 8.99 10⁹ 14.0 10⁻⁶ 15.0 10⁻⁶ / 190²
Fe = 5.2296 10⁻³ N
The resulting force is
R = Fe - Fg
R = 5.2296 10⁻³ - 5.795 10⁻⁶= 5229.6 10⁻⁶ - 5,795 10⁻⁶
R = 5,224 10⁻³ N
this is a repulsive force and the asteroids move away from each other
The car on the top of the arc;
m = 1,400 kg, v = 15 m/s, r = 40 m;
The normal force:
F n = m g - m v ² / r =
= 1,400 kg · 9.8 m / s² - (1,400 kg · ( 15 m/s )² : 40 m ) =
= 13,720 N - 7,875 N = 5,845 N
Answer:
B ) 5,800 N
Answer:
Considerando, que al tope de la atmósfera llega un 100% de la radiación solar, de este total, sólo un 25% llega directamente a la superficie de la Tierra y un 25% es dispersado por la atmósfera como radiación difusa hacia la superficie, esto hace que cerca de un 50% de la radiación total incidente llegue a la ...
Explanation:
The force of a test charge would be doubled if the electric field is doubled.
Answer: Option A
<u>Explanation:</u>
Electric field is the region or range up to which a charge particle will have its influence of electric energy on another charged particles. So the experienced force by the test charge up to a certain range is defined as the electric field of that charged particle.
This means that the electric field strength is inversely proportionate to the test charge and directly proportionate to the force acting on the test charge. As
,
So, force will be product of electric field strength with test charge. Thus,
So, if there is increase in the electric field, then there will be increase in the force of the test charge. Thus, if the electric field is doubled thereby the force of a test charge will also be doubled.
Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s
Explanation:
For proton, the centripetal force required for circular motion is provided by the magnetic force,
so Fm= Fc
q v B = m v²/r
m= mass of charged particle
v= velocity
B =magnetic field
q= charge
r= radius of circular path
v= q B r/m
now v= r ω
ω= angular velocity
ω r = q B r /m
ω=q B /m
now ω= 2π/T where T =time period
so 2π/T=q B/m
T= 2 πm/q B
T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]
T= 7.28 x 10⁻⁸ s
