A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotat
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A) +5 J
B) +1 J
Explanation:
A)
The internal forces (interaction forces) acting on a system do not change the mechanical energy (sum of potential and kinetic energy) of the system.
However, these forces are responsible for converting the energy from one form into another; the work done by these forces is equal to the amount of energy converted from one form into the other.
In this problem, we have:
is the loss in potential energy of the system
is the gain in kinetic energy of the system
By looking at these numbers, this means that the internal forces have converted 5 J of energy from potential energy into kinetic energy (while the additional +1 J missing is due to external forces, as explained in part B).
Therefore, the work done by internal forces is
W = +5 J
B)
First of all, we calculate the change in mechanical energy of the system.
The mechanical energy of a system is the sum of its kinetic energy (K) and its potential energy (U):
So, the change in mechanical energy is equal to the sum of the changes of kinetic energy and the changes of potential energy:
In this problem:
So, the change in mechanical energy is:
According to the work-energy theorem, the work done by external forces on a system is equal to the change in mechanical energy of the system: therefore in this case, the work done by external forces is
Hi you didn't provide any images to solve the question, hence I am going to solve a different question of same concept so you can have an idea how to tackle such types of questions.(please refer to the attachment for question)
Answer:
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Explanation:
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1) The electric force changes by a factor of 25
2) The electric force changes by a factor of 16/9
Explanation:
1)
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, let's call F the initial force between the two charges when they are at a distance of r.
Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is
r' = 5r
Therefore, the new force between the charges is:
So, the force has changed by a factor of 25.
2)
The original force between the two charges is
In this problem, we have:
- The distance between the charges is changed by a factor of 6:
r' = 6r
- The charges are both changed by a factor of 8:
Substituting into the equation, we find the new force:
So, the force has changed by a factor of 16/9.
Learn more about electric force:
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