V 1= 3.00 · 10^8 m/s
v 2 = 2.00 · 10^8 m/s
The index of refraction:
n = v 1 / v 2 = 3.00 · 10^8 m/s : 2.00 · 10^8 m/s = 1.5
Answer:
The index of refraction of that medium is 1.5
Explanation:
(a) Find the magnitude of the angular acceleration of the wheel.
- angular acceleration = angular speed /time
- angular acceleration = 12.9/2.98 = 4.329rad/s²
(b) Find the angle in radians through which it rotates in this time interval.
- angular speed = 2x3.14xf
- 12.9rad = 2 x3.14
- rad = 6.28/12.9
- rad = 0.487
Now we convert rad to angle
- 1 rad = 57.296°
- 0.487 = unknown angle
- unknown angle =57.296 x 0.487 = 27.9°
The angle in radians = 27.9°
Answer:
Because winding roads have a gentle slope on hills, so it's easy to climb it than a steepy.
The period T of a pendulum is given by:

where L is the length of the pendulum while

is the gravitational acceleration.
In the pendulum of the problem, one complete vibration takes exactly 0.200 s, this means its period is

. Using this data, we can solve the previous formula to find L:
Answer:
B. 6 cm
Explanation:
First, we calculate the spring constant of a single spring:

where,
k = spring constant of single spring = ?
F = Force Applied = 10 N
Δx = extension = 4 cm = 0.04 m
Therefore,

Now, the equivalent resistance of two springs connected in parallel, as shown in the diagram, will be:

For a load of 30 N, applying Hooke's Law:

Hence, the correct option is:
<u>B. 6 cm</u>