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2 years ago

What is the colour of third band of a coded resistor having resistance equal equal to 2.3*10`2

Physics

1 answer:

Helen [10]2 years ago

4 0

Color of third band of a coded resistor is Brown.

What is Resistance:

Resistance is a measure of the opposition to current flow in an electrical circuit.
Resistance is measured in ohms, omega (Ω)

The color code specify the resistance value, the tolerance, and sometimes the reliability or failure rate.

How to identify resistor's color codes:

Look at the resistor so the group of 3 or 4 color bands are on the left side
Read the color bands from left to right.
Read the color on the last color band, which is farthest right.
compare the colors to the resistance code table

Here,

the value of resistance is 2.3x10^2 Ω

R = 23x10^1 Ω

here power of 10 is 1

so, the color of third band of a color coded resistor will be related to number 1

Hence,

color of third band of a coded resistor is Brown.

Learn more about resistor's color codes here:

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Soloha48 [4]

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3 years ago

Explain how you would find the mass percent of each element in water

Maru [420]

Percent composition is the percent by mass of each element present in a compound. In that compound, there are two moles of H atoms and 2 x 1.008 = 2.016 grams. That's how many grams of hydrogen are present in one mole of water. There is also one mole of oxygen atoms weighing 16.00 grams in the mole of water.

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4 years ago

Three different experiments are conducted that pertain to the oscillatory motion of a pendulum. For each experiment, the length

svetlana [45]

Answer:

Check the explanation

Explanation:

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Thus w angular frequency of oscillation is√(g/l)

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3 years ago

A convex lens of focal length 25 cm is in contact with a concave lens of focal length 50 cm. The equivalent focal length of this

Gwar [14]

The equivalent focal length of this combination-lenses should be +50 cm.

Given:

Focal length of convex lens, f₁ = +25 cm

Focal length of concave lens, f₂ = -50 cm

Calculation:

We know that the power of a lens is given as:

P = 1 / f

where, f is the focal length of lens

Now, the power of convex lens can be calculated as:

P₁ = 1/f₁

= 1/(25×10⁻² m)

= 100/25

= +4 D

Similarly, the power of concave lens can be calculated as:

P₂ = 1/f₂

= (1/-50×10⁻² m)

= -100/50

= -2 D

Thus, the power of the combined lenses can be calculated as:

P₍₁₊₂₎ = P₁ + P₂

= +4 D - 2 D

= +2 D

Now, the combined focal length of the lens can be calculated as:

f₍₁₊₂₎ = 1 / P₍₁₊₂₎

= 100 / 2 D

= +50 cm

Therefore, the equivalent focal length of this combination-lenses will be +50 cm.

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2 years ago

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Zolol [24]

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