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Aleks [24]
2 years ago
9

A common design for a spotlight uses a lens and a mirror, combined with a gas-discharge lamp, to project a powerful parallel bea

m of light. Where are the lens and mirror positioned?
Physics
1 answer:
wel2 years ago
7 0

Answer:

Explanation:

For answer please see the image attached .

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Earth is the only planet able to support _____.
Sergeeva-Olga [200]
<span>Earth is the only planet able to support _____

Life
</span>
3 0
3 years ago
The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re
mihalych1998 [28]

Answer:

Explanation:

Given

\omega =13-\frac{1}{2}\cdot t^2

Motor reverse its direction when \omega =0

13-0.5t^2=0

26=t^2

t=\sqrt{26}=5.099\approx 5.1 s

(b)

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

\int d\theta =\int_{0}^{5.1}\omega dt

\int d\theta =\int_{0}^{t}(13-.05t^2)dt

\theta =(13t-0.1667\times t^3)_0^{5.1}

\theta =44.192^{\circ}

4 0
3 years ago
An object located near the surface of Earth has a weight of a 245 N
marusya05 [52]

Answer:

The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.

Explanation:

Weight of the object on the surface of Earth, W = 245 N

On the surface of Earth, acceleration due to gravity, g = 10 m/s²

Weight of an object is given by :

W = mg

m is mass

m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg

So, the mass of the object is 24.5 kg

Acceleration due to gravity on Mars, g' = 3.72 m/s²

Weight of the object on Mars,

W' =mg'

W' = 24.5 kg × 3.72 m/s²

= 91.14 N

So, the weight of the object on Mars is 91.14 N.

4 0
3 years ago
If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.
Sliva [168]

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225  - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\

Therefore, his acceleration rate is -0.00186 m/s²

6 0
3 years ago
Will give brainliest to right answer!
viva [34]
The correct answer is D.
8 0
3 years ago
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