Imagine an infinite earth with a hole dripped through it. You fall in and accelerate at g~10m/s/s. How long until you reach the
1 answer:
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Answer:
The answer is 12.27 g (NH4)3PO4
Explanation:
Step 1: balance the chemical equation:
H3PO4 + 3NH3 → (NH4)3PO4
step 2: the molar masses of each of the reagents and products are calculated using the periodic table:
H3PO4:
3 atoms of H: 3x1=3 g/mol
1 atom of P: 1x30.97=30.97 g/mol
4 atoms of O: 4x16=64 g/mol
Molar mass=3+30.97+64=97.97 g/mol
3NH3:
3 atoms of N: 3x14=42 g/mol
9 atoms of H: 9x1=9 g/mol
Molar mass=42+9=51 g/mol
(NH4)3PO4:
3 atoms of N: 3x14=42 g/mol
12 atoms of H: 12x1=12 g/mol
1 atom of P: 1x30.97=30.97 g/mol
4 atoms of O: 4x16=64 g/mol
Molar mass=42+12+30.97+64=148.97 g/mol
we make a rule of three to calculate the amount of ammonium phosphate:
51 g NH3------------------148.97 g (NH4)3PO4
4.2 g NH3-----------------x g (NH4)3PO4
Clearing the x, we have:
Answer:
120 m
Explanation:
Given:
wavelength 'λ' = 2.4m
pulse width 'τ'= 100T ('T' is the time of one oscillation)
The below inequality express the range of distances to an object that radar can detect
τc/2 < x < Tc/2 ---->eq(1)
Where, τc/2 is the shortest distance
First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'
f = c/λ (c= speed of light i.e 3 x m/s)
f= 3 x / 2.4
f=1.25 x hz.
As, T= 1/f
time of one oscillation T= 1/1.25 x
T= 8 x s
It was given that pulse width 'τ'= 100T
τ= 100 x 8 x => 800 x
s
From eq(1), we can conclude that the shortest distance to an object that this radar can detect:
= τc/2 => (800 x
x 3 x
)/2
=120m