To solve this problem we will start from the definition of the decibels which refers to the log relationship of the intensities, mathematically each decibel of the people can be described as follows





For properties of the logarithm then we have that,


We have the relation



Answer:
Average force exerted by the water on the blades is 1024 N
Explanation:
As we know that the force due to water jet is given by

here we know that



so here we will have


Average force exerted by the water on the blades is 1024 N
Compression is the best answer. Think about pressing on the toy bus enough to bend the table but not break it
Answer:
The percentage of its mechanical energy does the ball lose with each bounce is 23 %
Explanation:
Given data,
The tennis ball is released from the height, h = 4 m
After the third bounce it reaches height, h' = 183 cm
= 1.83 m
The total mechanical energy of the ball is equal to its maximum P.E
E = mgh
= 4 mg
At height h', the P.E becomes
E' = mgh'
= 1.83 mg
The percentage of change in energy the ball retains to its original energy,
ΔE % = 45 %
The ball retains only the 45% of its original energy after 3 bounces.
Therefore, the energy retains in each bounce is
∛ (0.45) = 0.77
The ball retains only the 77% of its original energy.
The energy lost to the floor is,
E = 100 - 77
= 23 %
Hence, the percentage of its mechanical energy does the ball lose with each bounce is 23 %
<h2>
She will find the ball at a horizontal distance of 86.4 m from landed location</h2>
Explanation:
Consider the vertical motion of ball
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 2 m/s
Acceleration, a = 9.81 m/s²
Displacement, s = 100 m
Substituting
s = ut + 0.5 at²
100 = 2 x t + 0.5 x 9.81 xt²
4.905t² + 2t - 100 = 0
t = 4.32 s or t = -4.72 s
After 4.32 seconds the ball reaches ground.
Now we need to find horizontal distance traveled by ball in 4.32 seconds.
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 20 m/s
Acceleration, a = 0 m/s²
Time, t = 4.32 s
Substituting
s = ut + 0.5 at²
s = 20 x 4.32 + 0.5 x 0 x 4.32²
s = 86.4 m
She will find the ball at a horizontal distance of 86.4 m from landed location