Answer:
Induced emf, 
Explanation:
We have,
Number of turns in the coil, N = 40
Radius of coil, r = 3 cm = 0.03 m
The field increases from 0 to 0.75 T at a constant rate in a time interval of 225 s.
It is required to find the magnitude of the induced emf in the coil if the field is perpendicular to the plane of the coil. The induced emf is given by :
, is magnetic flux
So, the magnitude of induced emf is 
.
I've had a similar question on an assignment myself, so I'm going to assume it had the same idea.
When you organize them in such a way, the pattern that emerges tells you elements organized by atomic weight have the same number of valence electrons.
Hope this helps!
Answer:
(a) Number of electrons per second strike the target is 3.125 x 10¹⁵.
(b) Charge that strikes the target in 0.750 s is 3.75 x 10⁻⁴ C .
Explanation:
(a) Let n be the number of electrons per second strike the target. We know that current (I) is given by the relation :
I = n x e
Here e is charge of electron.
Substitute 0.500 x 10⁻³ A for I and 1.6 x 10⁻¹⁹ C for e in the above equation.
0.500 x 10⁻³ = n x 1.6 x 10⁻¹⁹
n = 3.125 x 10¹⁵
(b) Let q be the charge that strikes the target. We know that :
q = I x t
Here I is current and t is time.
Substitute 0.500 x 10⁻³ A for I and 0.750 s for t in the above equation,
q = 0.500 x 10⁻³ x 0.750
q = 3.75 x 10⁻⁴ C
Answer:
When an object moves in a straight line, it is said to be in linear motion. By Newton's first law of motion, a body tends to be in rest or motion in a straight line until a net non-zero force acts on it.
Rate of change of position with respect to time is known as velocity. Uniformly accelerated motion refers to the motion where the rate of change of velocity with respect to time is constant.
Kinematic equations can be used to measure different aspects of a linear motion:
v = u + a t
s = u t + 0.5 a t²
v²= u² + 2 a s
where, u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.
