Please help 2 sorry for last one it didnt go through
1 answer:
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Answer:
The solution for y = -1.
Step-by-step explanation:
Given:
....(1)
....(2)
So, to solve for y, first we solve for x in equation (2):
⇒
Dividing both sides by 2,
⇒
Now, substituting the value of x in equation (1):
⇒
⇒
⇒
⇒
⇒
Dividing both sides by 11,
⇒
Therefore, the solution for y = -1.
Option A: z + 1
Option B: 6 + w
Option D:
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
<u>To find which expressions are polynomial:</u>
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C:
Here, y have fractional exponent.
So, it is not a polynomial.
Option D:
By the definition, is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and are polynomials.