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svet-max [94.6K]
2 years ago
14

The explanation for the large space between particles in a gas is provided by ____. A. Boyle's law B. Dalton's law C. kinetic th

eory D. energy conservation
Chemistry
1 answer:
NeTakaya2 years ago
3 0

The explanation for the large space between particles in a gas is provided by the kinetic theory (option C).

<h3>What is the kinetic theory?</h3>

The kinetic theory is a scientific theory used in physics to understand the behavior of gases.

This theory (kinetic theory) indicates that molecular distances in gases are small when compared to the molecular sizes.

In conclusion, the explanation for the large space between particles in a gas is provided by the kinetic theory (option C).

Learn more about the kinetic theory here:

brainly.com/question/15357425

#SPJ1

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A 0.200 M solution of a weak acid, HA, is 9.4% ionized. Using this information, calculate Ka for HA.
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Initial concentration of weak acid HA = 0.200 M

and dissociation constant ({ \alpha}) is :

\qquad \sf  \dashrightarrow \:  \alpha =  \frac{dissociation \:  \: percentage}{100}

\qquad \sf  \dashrightarrow \:  \alpha =  \frac{9.4}{100}  = 0.094

Now, at initial stage :

  • \textsf{ Conc of HA = 0.200 M}

  • \textsf{Conc of H+ = 0 M}

  • \textsf{Conc of A - = 0 M}

At equilibrium :

  • \textsf{Conc of HA = 0.200 - 0.094(0.200) = 0.200(1 - 0.094) = 0.200(0.906) = 0.1812 M}

  • \textsf{Conc of H+ = 0.094(0.200)  = 0.0188 M}

  • \textsf{Conc of A - = 0.094(0.200)  = 0.0188 M}

Now, we know :

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}}

( big brackets represents concentration )

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.0188×0.0188}{0.1812}}

\qquad \sf  \dashrightarrow \: { K_a = \dfrac{0.00035344}{0.1812}}

\qquad \sf  \dashrightarrow \: { K_a \approx 0.00195 }

\qquad \sf  \dashrightarrow \:  {K_a \approx 1.9 × {10}^{-3} }

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