Answer: 4.1 g of barium precipitated.
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
Given : moles of barium = 0.030
Molar mass of barium = 137 g/mol
x= 4.1 g
Thus there are 4.1 g of barium that precipitated.
To me it looks like gas.
Gas- CORRECT!
Solid- incorrect because if this were a depiction of a solid then the particles would be much much closer together.
Liquid - incorrect because the particles would be a little more crowded together.
Plasma- I do not think that this answer is correct because, even though the spacing of particles is similar to the spacing of particles in plasma, the particles in plasma are charged particles(nuclei (+) and electrons(-)). Therefore, because the diagram doesn't have the particles labeled with charges, I believe that Plasma cannot be the correct answer.
Any questions?
We know that:
f * λ = c
<span>and
E = h*f
so,rearranging:
</span>
<span>E/h = C/λ
given:
h = </span><span>6.90 × 10^2 nm
</span><span>substituting the values:
E = </span> C/λ<span> x h
(c is the speed of light;that is 3x10^8 m/s)
</span> = 3x10^8 x 6.626x10^-34 / 6.90 x10^7m x 6.022x10^23
Hence,
using calculator:
we get,
E = 1.69 x 10^5 Joules
Answer:
a particle with jagged rough ends has a high rate of deposition
