Question

What is the length of the diagonal of the square shown below​

Answer 1

Answer:

c =7√2

Step-by-step explanation:

using the Pythagorean theorem we solve the diagonal ,where the two sides are given to find the hypotenuse.

c² =a² + b²

where c is the diagonal (hypotenuse fot thr triangle)

a and b are the legs (sides)

c² =7²+7²

c²= 98

c= √98

c=√49.√2

c=7√2

Answer 2

Answer:

7$\sqrt{2}$

Step-by-step explanation:

the diagonal d divides the square into 2 right angles.

using Pythagoras' identity in one of the right triangles , then

d² = 7² + 7² = 49 + 49 = 98 ( take square root of both sides )

d = $\sqrt{98}$ = $\sqrt{49(2)}$ = $\sqrt{49}$ × $\sqrt{2}$ = 7$\sqrt{2}$