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Pepsi [2]
2 years ago
9

Select the correct location on the image. Identify the magnetic north pole of Earth’s magnet.

Physics
1 answer:
OverLord2011 [107]2 years ago
8 0

The magnetic north pole of the earth's magnet is in the geographic south pole.

  • There are two magnetic and geographic poles each, north and south
  • The two geographic poles are the locations where the earth's axis of rotation passes through which is imaginary
  • The magnetic north and south poles are not the same as the geographic north and south poles
  • In a compass, the needle points to the magnetic north pole
  • By convention, the magnetic north pole corresponds to the geographic south pole
  • The magnetic south pole corresponds to the geographic north pole
  • The magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south pole

The magnetic north pole of the earth's magnet is the geographic south pole.

Learn more about earth's magnetism here:

brainly.com/question/3928159

#SPJ10

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If a 340 g ball has 2.4 J of kinetic energy, what is it's velocity?
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How much work was done by a hot air balloon to lift up a 100 Newton to a height of 300 meters?
Monica [59]

So, the work was done by that hot air-balloon is <u>30,000 J or 30 kJ</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. <u>Work is the amount of force exerted to cause an object to move a certain distance from its starting point</u>. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :

\boxed{\sf{\bold{W = F \times s}}}

With the following condition :

  • W = work (J)
  • F = force (N)
  • s = shift or displacement (m)

Now, the s (displacement) can be written as ∆h (altitude change) because the object move to vertical line. The formula can also be changed to:

\boxed{\sf{\bold{W = F \times \Delta h}}}

With the following condition :

  • W = work (J)
  • F = force (N)
  • \sf{\Delta h} = change of altitude (m)

If an object has mass, then the object will also be affected by gravity. Always remember that F = m × g. So that :

\sf{W = F \times \Delta h}

\boxed{\sf{\bold{W = m \times g \times \Delta h}}}

With the following condition :

  • W = work (J)
  • m = mass of the object (kg)
  • g = acceleration of the gravity (m/s²)
  • \sf{\Delta h} = change of altitude (m)

<h3>Problem Solving</h3>

We know that :

  • F = force = 100 N
  • \sf{\Delta h} = change of altitude 300 m

What was asked :

  • W = work = ... J

Step by step :

\sf{W = F \times \Delta h}

\sf{W = 100 \times 300}

\boxed{\sf{W = 30,000 \: J = 30 \: kJ}}

<h3>Conclusion</h3>

So, the work was done by that hot air-balloon is 30,000 J or 30 kJ.

<h3>See More :</h3>
  • Work that he had done to lift object brainly.com/question/26341717
  • Converting work to potential energy brainly.com/question/26487284
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Which of the following is true about APR
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