Answer:
F = 8.6 10⁻¹² N
Explanation:
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Em₀ = U = q ΔV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v²
Em₀ = Emf
e ΔV = ½ m v²
v =√ 2 e ΔV / m
v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)
v = √(1.8075 10¹⁶)
v = 1,344 10⁸ m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10⁻¹⁹ 1.344 10⁸ 0.4
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Emo = U = q DV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v2
Emo = Emf
.e DV = ½ m v2
.v = RA 2 e DV / m
.v = RA (2 1.6 10-19 51400 / 9.1 10-31)
.v = RA (1.8075 10 16)
.v = 1,344 108 m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10-19 1,344 108 0.4
F = 8.6 10-12 N
Answer:
The correct option is A)
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
Given that Dante is leading a parade across the main street in front of city hall.
Let, Initial location of parade is 0i+0j
One block of city is one units on the XY- graph
Statement 1: Parade marches the parade 4 blocks east, then 3 blocks south
New location of parade is 4i-3j
Statement 2: The parade marches 1 block west and 9 blocks north and finally stops.
Final location of parade is (4i-3j)+(-1i+9j)=3i+6j
Displacement is given by
Displacement = (Final destination)-(Initial destination)
Displacement = (3i+6j)-(0i+0j)=3i+6j
Thus,
Magnitude of displacement = 
= 6.71 m
Direction of displacement = 
= 
= 63.43 NE
Therefore, the correct option is A) Displacement: 6.71 m, Direction: 63.4 degrees north of east
Answer:
i think its C hope this is rhight have a good day
Explanation: