Answer:
Jennifer
Explanation:
she has more mass which means she is using more force
<h2>
Answer: (a)t=0.553s, (b)x=110.656m</h2>
Explanation:
This situation is a good example of the projectile motion or parabolic motion, in which the travel of the bullet has two components: x-component and y-component. Being their main equations as follows:
x-component:
(1)
Where:
is the bullet's initial speed
because we are told the bullet is shot horizontally
is the time since the bullet is shot until it hits the ground
y-component:
(2)
Where:
is the initial height of the bullet
is the final height of the bullet (when it finally hits the ground)
is the acceleration due gravity
<h2>Part (a):</h2>
Now, for the first part of this problem, the time the bullet elapsed traveling, we will use equation (2) with the conditions given above:
(3)
(4)
Finding
:
(5)
Then we have the time elapsed before the bullet hits the ground:
(6)
<h2>Part (b):</h2>
For the second part of this problem, we are asked to find how far does the bullet traveled horizontally. This means we have to use the equation (1) related to the x-component:
(1)
Substituting the knonw values and the value of
found in (6):
(7)
(8)
Finally:
Answer:
the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is 
Explanation:
The free-body diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;
- the peripheral velocity that is directed downward
along the y-axis
- the linear velocity
that is directed along the x-axis
Now;


Also,

where
(angular velocity) = 

∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is 
Answer:
8.3 x 10⁻⁷ C
Explanation:
Electric flux will enter the face at x=0 and exit at face x= 25 m
On the other faces , field lines are parallel so no flux will enter or exit .
Flux entering the face at x = 0
= electric field x face area
= 560 x 25 x 25 = 350000 weber
Flux exiting the face at x = 25
= 410 x 25 x25
= 256250 weber
Net flux exiting from cube ( closed face )
350000 - 256250 = 93750 web
Apply gauss'es theorem
Q / ε = Flux coming out
Q is charge inside the closed cube
Q / ε = 93750
Q = 8.85 x 10⁻¹² x 93750
= 8.3 x 10⁻⁷ C