C. 0.37V. A capacitor of 650x10⁻⁴F that stores 24x10⁻³C has a potential difference of 0.37V between its plates.
The key to solve this problem is using the capacitance equation C = Q/Vᵃᵇ, where C is the capacitance, Q the charge stored in the plates, and Vᵃᵇ the potential difference between the plates.
A 650x10⁻⁴F capacitor stores 24x10⁻³C, clear Vᵃᵇ for the equation:
C = Q/Vᵃᵇ -----------> Vᵃᵇ = Q/C
Solving
Vᵃᵇ = 24x10⁻³C/650x10⁻⁴F = 0.37V
The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
<h3>
Work done by the force experienced by the object</h3>
The magnitude of the work done by force experience by the object is calculated as follows;
W = f.d
where;
- F is the applied force (2xyi + 3yj), where x and y are in meters
- d is the displacement of the object = (a, b)
The work done by the force is determined from the dot product of the force and the displacement of the object.
F = (2xyi + 3yj).(a + b)
W = (2abi + 3bj).(ai + bj)
W = (2a²b + 3b²)J
Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.
The complete question is below:
The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.
How much work does the force do?
Learn more about work done here: brainly.com/question/8119756
A material you are testing conducts electricity but cannot be pulled into wires. It is most likely a metalloid. Hope this helps!
Answer:
C-less than
Explanation:
Distance is total distance traveled (1000m here if you stop where you started).
Displacement is your final distance from where you started (0m if you stop where you started).
0m<1000m
